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3 years ago

If you compare the red triangle to the blue triangle are the figures similar, congruent, neither, or it is impossible to tell?

Mathematics

1 answer:

bixtya [17]3 years ago

3 0

Answer:

Congruent

Step-by-step explanation:

Congruent figures are all figures that have the same number of sides, with the same length, and the angles between the sides have the same values.

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John is interested in purchasing a multi-office building containing five offices. The current owner provides the following proba

Elenna [48]

Answer:

Option B.

Step-by-step explanation:

The given table is:

Number of Lease Offices : 0 1 2 3 4 5

Probability : 5/18 1/4 1/9 1/18 2/9 1/12

The expected probability is

Expected probability = $\sum_{i=0}^5 x_{i}p(x_i)$

Expected probability = $0p(0)+1P(1)+2P(2)+3P(3)+4P(4)+5P(5)$

Expected probability = $0\cdot (\frac{5}{18})+1\cdot (\frac{1}{4})+2\cdot (\frac{1}{9})+3\cdot (\frac{1}{18})+4\cdot (\frac{2}{9})+5\cdot (\frac{1}{12})=\frac{35}{18}$

It is given that the yearly lease = $12,000.

The yearly leases for the whole building in a given year is

Yearly leases = $\frac{35}{18}\times 12000=23333.3333333\approx 23333.33$

Therefore, the correct option is B.

3 0

4 years ago

Dave's age in 4 years is 18. Write an equation that represents Dave's age in 4 years.

julsineya [31]

This equation might be x + 4 =18

3 0

4 years ago

Read 2 more answers

5 divided by one over A hundred

Vika [28.1K]

Work

$\frac{5}{1}$ ÷ $\frac{1}{100}$

Keep the first fraction, change the sign, flip the second fraction.

$\frac{5}{1}$ x $\frac{100}{1}$ = $\frac{500}{1}$

Answer

$\frac{500}{1}$ or 100

5 0

4 years ago

Read 2 more answers

1, 3, 7, 15, 31 next two terms in the nsequence

alexira [117]

1 + 2^1 = 3

3 + 2^2 = 7

7 + 2^3 = 15

15 + 2^4 = 31

31 + 2^5 = 63

63 + 2^6 = 127

so the next two terms in the sequence 1, 3, 7, 15, 31, is 63 and 127.

3 0

3 years ago

Read 2 more answers

PLZ HELP MARKIN BRAINIEST!!!

Lady_Fox [76]

Answer:

Step-by-step explanation:

The first question is asking you how many visitors there were, using the function model provided, when x = 0. Filling that in gives you:

$y=18,582(.90)^0$

Anything to the 0 power = 1, so

y = 18,582(1) and

y = 18,582

The second question is asking you how many visitors there were on the 9th weekend, when x = 9:

$y=18,582(.90)^9$ and

$y=18,582(.387420489)$ so

y = 7199

The last question is asking on what weekend (unknown x) are there

y = 15.051 visitors. That requires using a log to solve for x. Set it up first:

$15,051=18,582(.90)^x$

Start by dividing both sides by 18,582 to get:

$.8099773975=(.90)^x$

Now we need to take the log of both sides to get that x out from its exponential position. By taking the log of the right side, we are given the ability to bring the x down in front:

log(.8099773975) = x log(.90)

Now divide both sides by log(.90) to get

x = 2.000

That means that on the second weekend, there were approximately 15,051 visitors.

7 0

4 years ago