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kati45 [8]
3 years ago
9

Kaitlin works with her clients to increase visibility and use of their websites using

Business
1 answer:
Hatshy [7]3 years ago
3 0

Answer:

search marketing strategist

Explanation:

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You are an occupational health nurse in a large ceramic manufacturing company. how would you intervene to prevent occupational l
Ira Lisetskai [31]

As a health nurse here are some prevention methods for lung diseases for the people that work in ceramic industry that everyone should be aware of:

  • Make sure to use a ceramic mask when you are working or mixing the clay to make sure you do not inhale any fine particles.
  • At all costs unnecessary exposure to the dust should be avoided as these dust particles when inhaled decrease the lung capacity.
  • Do not eat or drink at your working place as these will again go through your system leading to any damages.
  • Always be aware of the ingredients that are using if they are harmful the management should be made aware so that it doesn't harm when working with them.
  • Good and clean working environment with a flow of fresh air should be insured.

To know more about lung diseases refer to the link below

brainly.com/question/15645636

#SPJ4

3 0
2 years ago
A cylindrical part of diameter d is loaded by an axial force p. this causes a stress of pya, where a 5 pd2y4. if the load is kno
raketka [301]

Here is the correct question.

A cylindrical part of diameter d is loaded by an axial force p. this causes a stress of P/A, where A= πd²/4. if the load is known with an uncertainty of ±10 percent, the diameter is known within ±5 percent (tolerances), and the stress that causes failure (strength) is known within ±15 percent, determine the minimum design factor that will guarantee that the part will not fail.

Answer:

the minimum design factor that will guarantee that the part will not fail. = 1.434

Explanation:

Looking at the uncertainty; loss of strength must be raised to \dfrac{1}{0.85} due to the stress that causes the failure (strength)  is known within ±15% uncertainty.

Looking at the uncertainty; the maximum allowable load  must be reduced to \dfrac{1}{1.1} because the load is known with an uncertainty of ±10.

Looking at the uncertainty; the diameter must be raised to \dfrac{1}{0.95}  because the diameter is known within an uncertainty of ±5.

The decrease in the maximum allowable stress can be estimated as:

\sigma' = \dfrac{P'}{A'}

where,

\sigma = stress

P = load

A = cross-sectional area of the cylinder

∴

\sigma' = \dfrac{P'}{\dfrac{\pi}{4}(d')^2}

replacing P' with \dfrac{1}{1.1}P   and d' with \dfrac{1}{0.95}d, we have:

\sigma' = \dfrac{(\dfrac{1}{1.1})\times p }{\dfrac{\pi}{4}(\dfrac{1}{0.95 } d)^2 }

\sigma' =\dfrac{P}{\dfrac{\pi}{4}d^2} (\dfrac{\dfrac{1}{1.1} }{(\dfrac{1}{0.95})^2 }) }

\sigma' =\sigma \times (\dfrac{\dfrac{1}{1.1} }{(\dfrac{1}{0.95})^2 }) }

\sigma' =\sigma \times 0.82045

\dfrac{\sigma' }{\sigma } =0.82045

Thus, the uncertainty in diameter and the load of the allowable stress needs to decrease to 0.82045

Now, the minimum design factor that will ascertain that the part will not fail can be computed as:

n_d = \dfrac{loss  \ of  \ function \  parameter }{maximum \  allowable \ parameter}

where;

the design factor = n_d

n_d =\dfrac{\dfrac{1}{0.85} }{0.82045}

the design factor  n_d = 1.434.

Thus,  the minimum design factor that will guarantee that the part will not fail. = 1.434

7 0
3 years ago
Which of the following is true?Select one:a. Overhead costs are often affected by many issues and are frequently too complex to
Vsevolod [243]

Answer:

e. When cost analysts are able to logically trace cost objects to costs, costing accuracy is improved.

Explanation:

Overhead costs are costs which can not be attributed to a particular item . So it is distributed among more than one item on some basis.

For example electricity cost is a common overhead in a company having two machines one producing pen and the other producing paper . The overhead electricity cost can be scientifically apportioned in the cost analysis of pen and paper on the basis of wattage capacity of machines used in the manufacture of pen and paper .

6 0
3 years ago
The term random walk is used in investments to refer to ______________.A. stock price changes that are random but predictableB.
castortr0y [4]

Answer:

C. stock price changes that are random and unpredictable

Explanation:

Random walk -  

In terms of business ,

This theory determines the changes in the prices of stock are not related to each other and are basically completely random and can not be predicted .

Hence , the past details can not forecast the present changes in the stock market .

Hence , the correct statement about random walk is  ( c ) .

3 0
4 years ago
Shep goes to his favorite coffee shop every morning and always buys one large latte, no matter whether there is a special or not
lozanna [386]

Answer:

Price elasticity of demand = 0

Explanation:

The price elasticity of demand is zero because Shep's demand for lattes is perfectly inelastic since an alteration in price (i.e., half-price Mondays) does not affect consumption in the slightest, which means that he will always consume exactly one latte every morning regardless of price.

3 0
4 years ago
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