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rjkz [21]
3 years ago
6

Which is an example of a statistical question?

Mathematics
2 answers:
salantis [7]3 years ago
6 0

Answer:

How old are the students in math class?

Step-by-step explanation:

the students in ur class have a more probablity that the age will closely be the same as urs.

Molodets [167]3 years ago
3 0

Answer:

How old are the students in math class?

Step-by-step explanation:

A statistical question is one that can be answered by collecting data and where there will be variability in that data. For example, there will likely be variability in the data collected to answer the question, "How much do the animals at Fancy Farm weigh?" but not to answer, "What color hat is Sara wearing?".

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The answer is . (one [point] 4)

((Yes, its correct, checked and took an exam on it))
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You randomly choose one of the tiles out of a bag with the numbers 5,6,7,8,9,10,20 written on the tiles. Without replacing the f
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What is the value of x in the equation StartFraction 4 Over 7 EndFraction (StartFraction 21 Over 8 EndFraction x + one-half) = n
Sliva [168]

Answer:

<h2>x = -0.5</h2>

Step-by-step explanation:

\dfrac{4}{7}\left(\dfrac{21}{8}x+\dfrac{1}{2}\right)=-2\left(\dfrac{1}{7}-\dfrac{5}{28}x\right)\\\\\text{use the distributive property}\ a(b\pm c)=ab\pm ac\\\\\left(\dfrac{4}{7}\right)\left(\dfrac{21}{8}x\right)+\left(\dfrac{4}{7}\right)\left(\dfrac{1}{2}\right)=(-2)\left(\dfrac{1}{7}\right)-(-2)\left(\dfrac{5}{28}x\right)\\\\\dfrac{4\cdot21}{7\cdot8}x+\dfrac{4\cdot1}{7\cdot2}=-\dfrac{2}{7}+\dfrac{2\cdot5}{28}x\qquad\text{simplify}

\dfrac{3}{2}x+\dfrac{2}{7}=-\dfrac{2}{7}+\dfrac{5}{14}x\qquad\text{multiply both sides by 14}\\\\(14)\left(\dfrac{3}{2}x\right)+(14)\left(\dfrac{2}{7}\right)=(14)\left(-\dfrac{2}{7}\right)+(14)\left(\dfrac{5}{14}x\right)\qquad\text{simplify}\\\\(7)(3x)+(2)(2)=(2)(-2)+(1)(5x)\\\\21x+4=-4+5x\qquad\text{subtract 4 from both sides}\\\\21x+4-4=-4-4+5x\\\\21x=-8+5x\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\21x-5x=-8+5x-5x\\\\16x=-8\qquad\text{divide both sides by 16}

\dfrac{16x}{16}=\dfrac{-8}{16}\qquad\text{simplify}\\\\\boxed{x=-\dfrac{1}{2}\to x=-0.5}

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3 years ago
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Find the area of a regular pentagon with a side of 10cm and an apothem of 6.9cm
svetlana [45]
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4 years ago
Leonhard wants to place a triangular-based cabinet in the corner of his rectangle-shaped living room. The triangular base has a
almond37 [142]

Answer:

A. x=\frac{-7+\sqrt{193}}{4}

Step-by-step explanation:

We have, the dimensions of the living room are 30 ft and 20 ft.

Thus, area of the living room = length × width = 30 × 20 = 600 ft².

Now, it is given that the cabinet takes 6% of the living room i.e. 6% of 600 ft² = 0.06 × 600 = 36 ft².

As, the triangle has dimensions (2x+3) ft and (3x+6) ft.

So, the area of the triangle = \frac{1}{2}\times base\times height

i.e. Area of cabinet = \frac{1}{2}\times (2x+3)\times (3x+6)

i.e. Area of cabinet = \frac{3}{2}\times (2x+3)\times (x+2)

i.e. Area of cabinet = \frac{3}{2}\times (2x^2+7x+6)

Since, the cabinet takes 6% of the living room, we have,

\frac{3}{2}\times (2x^2+7x+6) = 36

i.e. 2x^2+7x+6=36\times \frac{2}{3}

i.e. 2x^2+7x+6=24

i.e. 2x^2+7x-18=0

Further, as the solution of a quadratic equation ax^{2}+bx+c=0 is given by x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

On comparing we have, a=2, b=7, c= -18.

Thus, x=\frac{-7\pm \sqrt{7^{2}-4\times 2\times (-18)}}{2\times 2}

i.e. x=\frac{-7\pm \sqrt{49+144}}{4}

i.e. x=\frac{-7\pm \sqrt{193}}{4}

i.e. x=\frac{-7+\sqrt{193}}{4} and x=\frac{-7-\sqrt{193}}{4}

So, according to the options, we have,

A. x=\frac{-7+\sqrt{193}}{4} is the correct value of x.

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3 years ago
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