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Nimfa-mama [501]
3 years ago
6

A cube has a side length A. The side lengths ate decreased by 20%. Write an expression in simplest form.

Mathematics
2 answers:
Simora [160]3 years ago
8 0
20 is the anwser for example look at the side lengths measure them with the cm ruler
vazorg [7]3 years ago
5 0
The answer is: A-(20%)A
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6k^3+10k^2−56k and 5(7k−3)(3k−7)share a common binomial factor. What binomial factor do they share?
goldenfox [79]

Answer:

Step-by-step explanation:

6k^3+10k^2-56k\\2k(3k^2+5k-28)\\=2k[3k^2+12k-7k-28]\\=2k[3k(k+4)-7(k+4)]\\=2k(k+4)(3k-7)

common factor is 3k-7

8 0
2 years ago
Simplify: 2 (5 + 3x) + (x + 10)
IgorLugansk [536]
10 + 15x + x + 10
= 16x + 20
6 0
3 years ago
Circle A has center of (2, 8), and a radius of 2 and circle B has a center of (5, 4), and a radius of 10. What steps will help s
Viktor [21]

Answer:

1. Translate circle A using the rule (x − 3, y + 4).

4. Dilate circle A by a scale factor of 5

Step-by-step explanation:

we know that

All circles are similar figures

step 1

Translate the center of circle A to the center of circle B

we have

A(2,8) -----> B(5,4)

so

The rule of the translation is

(x,y) ----> (x+a,y+b)

(2,8) ----> (2+a,8+b)

2+a=5 ----> a=5-2=3

8+b=4 ---> b=4-8=-4

therefore

The rule of the translation is

(x,y) ----> (x+3,y-4)

step 2

Divide the radius of circle B to the radius of circle A to find out the scale factor

10/2=5

so

Multiply the radius of circle A by the scale factor to obtain the radius of circle B

therefore

Dilate circle A by a scale factor of 5

3 0
3 years ago
Pls I need help please :D its math and you'll get 30 points<br><br> Its a picture
Amanda [17]

Answer:

5,750

Step-by-step explanation:

if he has 10 of each then you can multiply each bag by 10 and then multiply the amount of bags to the amount the coin is worth

5 0
3 years ago
Find the distance between the points (3, –8) and (0, –9).
nadezda [96]

The formula for distance between two points is:

\sqrt{(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2}}

In this case:

x_{2} =0\\x_{1} =3\\y_{2} =-9\\y_{1} =-8

^^^Plug these numbers into the formula for distance like so...

\sqrt{(0-3)^{2} + (-9 - (-8))^{2}}

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses. Remember that when solving you must go from left to right

\sqrt{(0-3)^{2} + (-9-(-8))^{2}}

0 - 3 = -3

\sqrt{(-3)^{2} + (-9-(-8))^{2}}

-9 - (-8) = -1

\sqrt{(-3)^{2} + (-1)^{2}}

Next solve the exponent. Again, you must do this from left to right

\sqrt{(-3)^{2} + (-1)^{2}}

(-3)² = 9

\sqrt{9 + (-1)^{2}}

(-1)² = 1

\sqrt{(9+1)}

Now for the addition

\sqrt{(9+1)}

9 + 1 = 10

√10 <<<This can not be further simplified so this is your exact answer

Your approximate answer would be about 3.16

***Remember that the above answers are in terms of units

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0
2 years ago
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