I think a is (8,-8)
B) (0,8)
Answer:
The line AB, with A(Ax, Ay), B(Bx, By) and midpoint M(Mx, My) satisfying:
Ax + Bx = 2Mx
Ay + By = 2My
=>
2 + Bx = 2*1
5 + By = 2*2
=> Bx = 0
=> By = -1
=> B(0, -1)
Hope this helps!
:)
Answer:
Step-by-step explanation:
dy/dx= -(2x+3y+1)/(3x-2y+1)
Let x= X+p. and y = Y+q. then dy/dx = dy/dX.
dy/dX= -(2X+2p+3Y+3q+1)/(3X+3p-2Y-2q+1) =
dy/dX = -{2X+3Y+(2p+3q+1)}/{3X-2Y+(3p-2q+1)}
Now 2p+3q+1=0……………..(1)
3p-2q +1=0…………………………(2)
p/(3+2)=q/(3–2)=1/(-4–9)
Answer:
In summation form 
Step-by-step explanation:
Within one hour, the first person gives a stack of flyers to six people and within the next hour, those six people give a stack of flyers to six new people.
So, in the first 5 hours, the summation of people that receive a stack of flyers not including the initial person will be given by
6 + (6 × 6) + (6 × 6 × 6) + (6 × 6 × 6 × 6) + (6 × 6 × 6 × 6 × 6).
So, in summation form 
Therefore, Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 6 (6) Superscript n minus 1, gives the correct solution. (Answer)
Answer:
y = 2x -33
Step-by-step explanation:
The line segment from the center (6, 4) to the given point (16, -1) is a radius of the circle. It is perpendicular to the tangent. Hence you need to write the equation of a line through point (16, -1) that is perpendicular to the line through that point and (6, 4).
The slope of the radius is ...
... ∆y/∆x = (-1-4)/(16-6) = -5/10 = -1/2
The slope of the tangent is the negative reciprocal of that, so is ...
... m = -1/(-1/2) = 2
In point-slope form, the tangent line through (16, -1) is
... y = m(x -h) +k
... y = 2(x -16) +(-1)
Simplifying, this is ...
... y = 2x -33