I've attached a photo of the solution below. Hope it helps!
The average of 4, 9, 16, 25 and x is 2x means that;
(4+9+16+25+x)/5=2x
Multiply both side by 5
5(54+x)/5=2x(5)
54+x=10x
Subtract x to both side
54+x-x=10x-x
54=9x
Divided 9 to both side
54/9=9x/9
x=6
Check:
Substitute x with 6
(4+9+16+25+x)/5=2x
(4+9+16+25+6)/5=2(6)
60/5=12
12=12; so x=6 which marks B as the correct answer. Have a nice day!
Given that the amount of fiber in 100 grams of beans is 3.6 grams the amount of fiber consumed from
of the small tin is <u>4.8 grams</u>.
<h3>How can the amount of fiber consumed be calculated?</h3>
From the given table, we have;
Mass of fiber in 100 g of beans = 3.6 grams
Mass of beans in the small tin = 200 grams
The quantity of the beans eaten =
of the small tin
Required:
The amount of fiber to consumed from eating
of the small tin
Solution;

Therefore;
The amount of fiber consumed by eating
of the small tin = <u>4.8 grams</u>
Learn more about fractions here:
brainly.com/question/20591763
Answer:
The probability is
≅ 
Step-by-step explanation:
Let's analyze the question.
There are 15 students in the 8th grade.
The students are randomly placed into three different algebra classes of 5 students each.
We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.
One possible way to solve this question is to think about the product probability rule.
We can use it because we are in an equiprobable space. (And also the events are independent).
Let's set for example a class for Evan.
The probability that Evan will be in a class is 
Then for Terry there are
places out of
that puts Terry in the Evan's class.
We write 
Finally for Trevor there are
places out of the remaining
that puts Trevor in the same class with Evan and Terry.
Using the product rule we write :

The probability of the event is
≅ 