We know that
<span>This problem can be represented through the following equation
</span>
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
<u>Answer</u>
<em>12 in by 12 in</em>
<u>Explanation</u>
The original length = x
This makes the length of the cube made to be = x - (2×2)
= (x - 4) in
height of the cube = 2 in
Volume of the cube = (x - 4) × (x - 4) × 2 = 128
= (x² - 8x + 16) × 2 = 128
= 2x² - 16x + 32 = 128
= 2x² - 16x + 32- 128=0
= 2x² - 16x - 96 = 0
= x² - 8x - 48 = 0
lets use the factor method to solve the quadrilatic equation above,
x² - 8x - 48 = 0
proctuct = -48
sum = -8
The two factors are; -12 and 8.
(x + 8)(x - 12) = 0
So the value of x are 12 and -8. Since x is a length, it can not be negative.
∴ x = 12 in.
The original dimensions of the sheet are <em>12 in by 12 in</em>.
12x-3y=3
y=4x-1
12x-3(4x-1)=3
12x-12x-3=3
24x=6
x=4
y=4(4)-1
y=15
x=4; y=15
The outer exponent is 4 so there will be 5 terms all together. By rules of exponents
C(4,0)(3^4)(2^0)(x^8)(y^0) + C(4,1)(3^3)(2^1)(x^6)(y^3) + C(4,2)(3^2)(2^2)(x^4)(y^6) + C(4,3)(3^1)(2^3)(x^2)(y^9) + C(4,4)(3^0)(2^4)(x^0)(y^12)
The coefficient of the 3rd term: C(4,2)(3^2)(2^2) = 6 x 9 x 4 = 216
Answer:
The coordinate r is the length of the line segment from the point (x,y) to the origin and the coordinate θ is the angle between the line segment and the positive x-axis.
Step-by-step explanation:
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