Hello.
-7h + 2(-4h + 5) > -4h + 1 + 10 ; solve for h
Our first step is to get rid of all the parenthesis. We can do this by simplifying everything out.
-7h - 8h + 10 > -4h + 11
Add like terms.
-15h + 10 > -4h + 11
Now, we must isolate our variables. We do this by moving all variables to one side and moving our other numbers to the other.
Subtract 10 from both sides. Then, add 4h to both sides.
-15h + 4h > 11 - 10
Simplify.
-h > 1
Divide both sides by -1.
However, keep in mind that when dividing with a negative, you must change the sign. Therefore, > turns into <
-h ÷ -1 < 1 ÷ -1
h < -1
Answer:
3/20 of the cover page is text about endangered species.
Step-by-step explanation:
We know that 3/8th of the page is text, and 2/5ths of that text is about endangered species.
So all we have to do is find out how much 2/5ths of 3/8ths are, which can be done simply via fraction multiplication.
3/8 * 2/5 = ?
For multiplying fractions, we multiply the top parts together, and then the bottom parts together. So 3/ 8 * 2/5 would be equal to (3*2) / (8*5). This gives us 6 / 40 which can be simplified to 3/20.
So 3/20ths of the cover page is about endangered animals.
Answer:
d
Step-by-step explanation:
If there are 15 nickels which is $0.75 and 12 dimes which is $1.20, then that would equal $1.95 and be 27 coins.
Answer:
Number of 12$ Shares? 25
Number of 14$ Shares? 57
Step-by-step explanation:
Let x = number of $12 shares.
Let y = number of $14 shares.
"Ivan has $1098 worth of $12 and $14 stock shares."
12x + 14y = 1098
The number of $14 shares is seven more than twice the number of $12 shares.
y = 2x + 7
We have a system of equations.
12x + 14y = 1098
y = 2x + 7
We can use the substitution method since the second equation is already solved for y. Substitute 2x + 7 for y in the first equation.
12x + 14(2x + 7) = 1098
12x + 28x + 98 = 1098
40x = 1000
x = 25
There are 25 $12 shares.
y = 2x + 7 = 2(25) + 7 = 57
There are 57 $14 shares.
Check:
25 × $12 + 57 × $1`4 = $300 + $798 = $1098
The total value is correct, so the answer is correct.
