Answer:
24
Step-by-step explanation:
Answer:
2002
Step-by-step explanation:
3421880 number of the different meals are possible.
<h3>What is the combination?</h3>
The arrangement of the different things or numbers in the number of the ways is called as the combination.
It is given that:-
Number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts.
So let's take each course by itself. You can choose 1 of 7 appetizers. So we have n = 7 After that, you chose an entre,
so the number of possible meals to this point is
n = 7 x 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 x 4 = 280
Therefore the number of possible meals you can have is 280. Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 x 1010 x 44 = 3421880
Therefore 3421880 different meals are possible.
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Her estimate is More than her actual earnings because since she earns 5.85 on an hourly wage I multiplied that by every hour she worked each day. her estimatewas $120 but her her actual earnings were 109.66.
Answer:
n = 59
Step-by-step explanation:
Since the difference between consecutive terms is constant, then the sequence is arithmetic.
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
Given
= 40, then
a₁ + 9d = 40 → (1)
Given
= 20, then
a₁ + 19d = 20 → (2)
Subtract (1) from (2) term by term
10d = - 20 ( divide both sides by 10 )
d = - 2
Substitute d = - 2 in (1)
a₁ - 18 = 40 ( add 18 to both sides )
a₁ = 58
The sum to n terms of an arithmetic sequence is
= 
[2a₁ + (n - 1)d ]
Here a₁ = 58, d = - 2 and = 0, thus
[ ( 2 × 58) - 2(n - 1)] = 0
( 116 - 2n + 2) = 0
Multiply through by 2
n(118 - 2n) = 0
Equate each factor to zero and solve for n
n = 0
118 - 2n = 0 ⇒ - 2n = - 118 ⇒ n = 59
However, n > 0 ⇒ n = 59
