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Katarina [22]
3 years ago
12

How do you simplify this

Mathematics
2 answers:
Anna11 [10]3 years ago
7 0

Answer:

6^8

Step-by-step explanation:

so whenever there is an exponent outside of a parentheses, multiply it with the exponent inside the parentheses:

so (6^4)^2= 6^8

Hope this helps!

borishaifa [10]3 years ago
3 0

Answer:

well the answer is 1679616

Step-by-step explanation:

how you search it up is (6^4)^2 and how you do it is times 6 by 6 by 6 by 6 then whatever that comes out to (1296) you would multiply that twice (1296 times 1296) and that'd be your answer ( 1679616)

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Answer: 27 hours

Step-by-step explanation: Have a nice day! :)

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Answer:

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Step-by-step explanation:

8×5×2=90

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8 0
3 years ago
What is the value of 4*(-1+2-3+4-3+6-7+....+100) Show your work. [Pls help I am really drowning in work. 50 points + brainliest
KengaRu [80]

Answer:

200

Step-by-step explanation:

We have:

4(-1+2-3+4-5+6-7...+100)

We can rearrange the numbers to obtain:

4((-1-3-5-7-...-99)+(2+4+6...+100))

From the left, we can factor out a negative. So:

4(-(1+3+5+7+...+99)+(2+4+6...+100))

In other words, we want to find the sum of all the odd numbers from 1 to 99.

And the sum of all the even numbers from 2 to 100.

Let's do each one individually:

Odd Terms:

We have:

(1+3+5+7+...+99)

We can use the arithmetic series formula, where:

S=\frac{k}{2}(a+x_k)

Where k is the number of terms, a is the first term, and x_k is the last term.

Since it's all the odd numbers between 1 and 99, there are 50 terms.

Our first term is 1 and our last term is 99. So, the sum of all the odd terms are:

S=\frac{50}{2}(1+99})

Divide the fraction. Add within the parentheses:

S=25(100)

Multiply:

S=2500

So, the sum of all the odd terms is 2500.

Even Terms:

We have:

(2+4+6+...+100)

Again, we can use the above formula.

Our first term is 2, last term is 100. And since it's from 2-100, we have 50 even terms. So:

S=\frac{50}{2}(2+100)

Divide and add:

S=25(102)

Multiply:

S=2550

We originally had:

4(-(1+3+5+7+...+99)+(2+4+6...+100))

Substitute them for their respective sums:

4(-(2500)+2550)

Multiply:

4(-2500+2550)

Add:

=4(50)

Multiply:

=200

So, the sum of our sequence is 200.

And we're done!

Note: I just found a <em>way</em> easier way to do this. We have:

4\cdot(-1+2-3+4-5+6-7+...+100)

Let's group every two terms together. So:

=4((-1+2)+(-3+4)+(-5+6)...+(-99+100))

We can see that they each sum to 1:

=4((1)+(1)+(1)+...+(1))

Since there are 100 terms, we will have 50 pairs, so 50 times 1. So:

=4(50)

Multiply:

=200

Pick which one you want to use! I will suggest this one though...

Edit: Typo

8 0
4 years ago
Y ∝ <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%7D" id="TexFormula1" title="\frac{1}{x}" alt="\frac{1}{x}" align="absmi
SashulF [63]
It should be your answer i think
4 0
3 years ago
2. The sum of the reciprocals of two consecutive positive integers is 17/72. Write an equation that can be used to find the two
Lena [83]
To answer this item, we let x be the first positive integer. Then, the second would be x+1. Their reciprocals would be 1/x and 1/(x+1). Then, the equation that would best represent the scenario above is,
                            1/x + 1/(x+1) = 17/72
Solving the equation above,
                           ((x+1) + x) / (x)(x+1) = 17/72
If we take the numerators of both sides of the equation,
                              (x+1) + x = 17
The value of x from the equation is 8 and x+1 would be 9. Thus, the answer would be 8 and 9. 
8 0
3 years ago
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