A) 5 to be chosen among a Total : 10 Men + 8 Women
¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five
b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56
So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees
c) 3 Women and 2 Men:
⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M
d) More women than men, it means:
3 W + 2 M OR (we have found it in c) = 2,520)
4 W + 1 M OR ⁸C₄ x ¹⁰C₁ →→→→ = 700
5 W + 0 M OR ⁸C₅ x ¹⁰C₀ →→→→ = 56
Total where W>M = 3,276 groups of 5 where women are at least 3
First we need to find the probability of selecting the 1 blue marble out of the 20 marbles total, which is 1/20.
Next, we need to find the probability of tossing the fair coin so it lands tails up, which is 1/2.
To find the probability of both events happening, we need to multiply the probabilities of the two individual events:
1/20 * 1/2 = 1/40
So the answer is 1/40, or 2.5%
Sorry about the poor formatting :( I'm on my phone at the moment, which makes it difficult.
Hope I helped, and let me know if you have any questions :D
Answer: D
Step-by-step explanation:
"-y (less than or greater than sign) 136" translates into two separate inequalities:
-y < 136 and -y > 136.
You want to solve for y in each case. To do this, multiply each inequality by "-1" and then immediately change the direction of the inequality sign.
For example: -1(-y < 136) => y > -136.
Answer:9
Step-by-step explanation:
3(5-2)
15-6
9
