Question

Let the sample space be S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Suppose the outcomes are equally likely. Compute the probability of the event E = ​"an odd number less than 7​."

Answer 1

Answer:

The probability is 3/5

Step-by-step explanation:

Given,

Sample space, S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10},

⇒ n(S) = 10,

Odd numbers less than 7 = 1, 2, 3, 4, 5 and 6

i.e. E = {1, 2, 3, 4, 5, 6}

⇒ n(E) = 6,

$\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

So, the probability of the event E,

$P(E) =\frac{n(E)}{n(S)}$

$=\frac{6}{10}$

$=\frac{3}{5}$