The width used for the car spaces are taken as a multiples of the width of
the compact car spaces.
Correct response:
- The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>
Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.
We have;
Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)
New space design = 16·x + 9×(a·x) = x·(16 + 9·a)
When the dimensions of the initial and new arrangement are equal, we have;
10 + 12·a = 16 + 9·a
12·a - 9·a = 16 - 10 = 6
3·a = 6
a = 6 ÷ 3 = 2
a = 2
Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;
10 + 12·a < 16 + 9·a
Which gives;
x·(10 + 12·a) < x·(16 + 9·a)
Therefore;
The initial total car park space is less than the space required for 16
compact spaces and 9 full size spaces, therefore; the store owners are
incorrect.
Learn more about writing expressions here:
brainly.com/question/551090
9/10 + 8/100
9/10 + 2×4/25×4
Common denominator is 50.
9/10 + 2/25.
5×9/5×10 + 2×2/2×25
45/50 + 4/50
= 49/50
Answer:
32r + 39
Step-by-step explanation:
<u>Step 1: Distribute</u>
4(5 + 8r) + 19
<em>20 + 32r + 19</em>
<em />
<u>Step 2: Combine like terms</u>
<em>32r + 39</em>
<em />
Answer: 32r + 39
Constants are anything that is not a variable. A variable is a letter. So think about it... What would be the constants? What is not a letter? TIP: Make sure you include - sign!_
Answer:
Answer: g(x)=. Step-by-step explanation: We are given that: f(x)=x². We have to find g(x). Since, we are given that g(3)=1. Hence, we will ... · g of x would equal (1/3x)^2 because if x was 6 y, g(x), would be 4
Step-by-step explanation:
