
![\textit{and their root difference is }4\frac{1}{3}\implies \cfrac{13}{3}\qquad so \\ \quad \\ \left[ \cfrac{-b+\sqrt{b^2-4(3)(10)}}{2(3)} \right]-\left[ \cfrac{-b-\sqrt{b^2-4(3)(10)}}{2(3)} \right]=\cfrac{13}{3} \\ \quad \\ \left[ \cfrac{-b+\sqrt{b^2-4(3)(10)}}{6} \right]+\left[ \cfrac{+b+\sqrt{b^2-4(3)(10)}}{6} \right]=\cfrac{13}{3} \\ \quad \\ \cfrac{-b+\sqrt{b^2-4(3)(10)}+b+\sqrt{b^2-4(3)(10)}}{6}=\cfrac{13}{3} \\ \quad \\ \cfrac{2\sqrt{b^2-4(3)(10)}}{6}=\cfrac{13}{3}](https://tex.z-dn.net/?f=%5Ctextit%7Band%20their%20root%20difference%20is%20%7D4%5Cfrac%7B1%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B13%7D%7B3%7D%5Cqquad%20so%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Cleft%5B%20%5Ccfrac%7B-b%2B%5Csqrt%7Bb%5E2-4%283%29%2810%29%7D%7D%7B2%283%29%7D%20%5Cright%5D-%5Cleft%5B%20%5Ccfrac%7B-b-%5Csqrt%7Bb%5E2-4%283%29%2810%29%7D%7D%7B2%283%29%7D%20%5Cright%5D%3D%5Ccfrac%7B13%7D%7B3%7D%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Cleft%5B%20%5Ccfrac%7B-b%2B%5Csqrt%7Bb%5E2-4%283%29%2810%29%7D%7D%7B6%7D%20%5Cright%5D%2B%5Cleft%5B%20%5Ccfrac%7B%2Bb%2B%5Csqrt%7Bb%5E2-4%283%29%2810%29%7D%7D%7B6%7D%20%5Cright%5D%3D%5Ccfrac%7B13%7D%7B3%7D%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Ccfrac%7B-b%2B%5Csqrt%7Bb%5E2-4%283%29%2810%29%7D%2Bb%2B%5Csqrt%7Bb%5E2-4%283%29%2810%29%7D%7D%7B6%7D%3D%5Ccfrac%7B13%7D%7B3%7D%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Ccfrac%7B2%5Csqrt%7Bb%5E2-4%283%29%2810%29%7D%7D%7B6%7D%3D%5Ccfrac%7B13%7D%7B3%7D)
and I'm pretty sure you can take it from there
Answer:
40
Step-by-step explanation:
First we need to subtract the 50 students enrolled in English class.
150 - 50 = 100
Next, let's add the mathematics students and the physics students.
80 + 60 = 140
Then we subtract the total amount of mathematics and physics students by the total number of students.
140 - 100 = 40
Therefore, there are 40 students who take both mathematics and physics.
Answer: I am so sorry if this doesn't help 135