Type the correct answer in the box. Spell the word correctly.

In computer science how can you define "copyright, designs and patents act 1988"?

Natali5045456 [20]

Answer:

:)

Explanation:

Copyright Designs and Patents Act

The Copyright Designs and Patents Act (1988) gives creators of digital media the rights to control how their work is used and distributed. ...

Anything which you design or code is automatically copyrighted and may not be copied without your permission, as the digital creator.

5 0

2 years ago

"Explain the functionality of the different layers found in the network protocol stack of an operating system such as Linux"

arsen [322]

Answer:

There are 7 layers in linux.

Explanation:

As networking is difficult and complex.

Imagine if every application had to know how to communicate on every step that would be more than just complex. So, rather than reinvent something which will help it to communicate let’s just make something that will automatically controls the communication and for that protocols came in to live.

As for the linux operating system, it is not exceptional from other operating systems.

There are 7 layers on network protocol stack use to communicate with other network protocol stack.

1. Application layer

2. System call interface

3. Protocol agnostic interface

4. Network protocol

5. Device agnostic interface

6. Device drivers

7. Physical hardware

All the layers vary in their functionality.

One more important thing to remember is that the network protocol stack layers is not one way its 2 way communication. First, when a client request to a network and second, when the request is full filled.

The top most layer is a part of user space, the next five layers comes in the kernel space and the final layer is the physical layer.

Application layer:

When a client or user request to a network the request initially comes to this layer.

On this layer we use tcp/ip protocol.

System call interface(SCI):

When application layer make a call to the kernel this layer handles that call. And take the request to the next layer.

Protocol agnostic interface:

This layer has two functions “talking” or “listening”. There is a thing called sockets which perform these functions and each socket has an id which is used specifically for an application.

Network protocol:

This layer is used for how the data is sent or received.

Device agnostic interface:

It is used to connect data from/to kernel user space and the network device drivers which allows the data to prepare itself for transmission over the medium from the network device.

Physical hardware :

This layer is responsible for the data packets transmission and received from the network medium being used whether cable or wireless.

5 0

3 years ago

what is a problem that occurs when someone registers purposely misspelled variations of well-known domain names?

laiz [17]

Answer:

Typosquatting

Explanation:

8 0

3 years ago

Task 03

Kamila [148]

Answer:

class Program {

public static void Main (string[] args) {

double number = 1.0;

while(number >= 0.001) {

Console.WriteLine (number);

number /= 2;

}

Explanation:

Always think carefully about what is in the condition of the while statement. In this case, you want the loop to be executed as long as the number is larger than or equal to 0.001.

3 0

1 year ago

Write a program that helps a young student learn to make change. Use the random number generator to generate change amounts betw

erastovalidia [21]

Answer:

#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

int quarters = coins/25;

coins = coins%25;

int dimes = coins/10;

coins = coins%10;

int nickles = coins/5;

coins = coins%5;

int pennies = coins/1;

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

}

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

int quarters = coins/25;

coins = coins%25;

int dimes = coins/10;

coins = coins%10;

int nickles = coins/5;

coins = coins%5;

int pennies = coins/1;

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

}

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}

Explanation:

Use the built-in rand function to generate a random coin.
Get all the required values for quarters, dimes, nickles and pennies and store them in variables.
Check if the coins give a value of temp, then answer is correct and the values of user will be added.
Optimum solution is displayed If it does not matches with the optimum solution. Display that the answer is wrong along with solution.

6 0

3 years ago