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MAXImum [283]
3 years ago
6

If the three operations were combined, O(logN) + O(N) * O(logN) + 1, the overall algorithm cost would be:________

Computers and Technology
1 answer:
KiRa [710]3 years ago
3 0

Answer:

D. O(NlogN)

Explanation:

The computation of the overall algorithm cost is as follows:

Given that

O(logN) + O(N) × O(logN) + 1

In the case of complexity we considered the high order that dominates the other terms

Thus, that term would be  

O(N) × O(logN)

It could be rewrite as

O(NlogN)

Hence, the correct option is D.

All the other options are wrong

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3 years ago
Write a loop that displays all possible combinations of two letters where the letters are 'a', or 'b', or 'c', or 'd', or 'e'. T
nikitadnepr [17]

Answer:

The program to this question can be given as:

Program:

#include <stdio.h> //include header file.

int main() //defining main method

{

char i,j; //defining variable

for  (i='a'; i<='e'; i++) //outer loop for column

{

for (j='a'; j<='e'; j++) //inner loop for row

{

printf("%c%c\n",i,j); //print value

}

}

return 0;

}

Output:

image.

Explanation:

  • In the above C language program, firstly a header file is included. Then the main method is defined in this, a method contains a char variable that is "i and j". This variable is used in for loop, that is used to print the pattern.
  • To print the following patter two for loop is used the outer loop is used for print columns and the inner loop prints row.
  • In C language to print character, we use "%c" inside a loop print function is used, that prints characters.

3 0
3 years ago
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