Question

If the side length of a square pyramid is tripled and the slant height is divided by 5, what would be the formula to find the modified surface area?

Answer 1

Answer:

$\large\boxed{S.A.'=9b^2+\dfrac{6}{5}bh}$

Step-by-step explanation:

The formula of a surface area of a square pyramid:

$S.A.=b^2+2bh$

b - side of the square

h - slant height

The new lenghts:

$3b$ - side of the square

$\dfrac{h}{5}$ - slant height

Substitute:

$S.A.'=(3b)^2+2(3b)\left(\dfrac{h}{5}\right)=9b^2+\dfrac{6}{5}bh$