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Sergio039 [100]
3 years ago
12

A horizontal line is seven which of the following is true

Mathematics
1 answer:
nydimaria [60]3 years ago
4 0

Answer:What are the answer choices??

Step-by-step explanation:

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Please I need help I was in the hospital just need 1,3,5,7,9 simplified
Tju [1.3M]
#1 is 125
#3 is 1/2
#5 is the same as the question
#7 is 5p^3 over 3
#9 is 4/5
3 0
3 years ago
A golfer’s arm rotates 1/2 of a revolution in 1/10 of a second. If the angular displacement is measured in radians, which statem
anyanavicka [17]
We know that

<span>The angular velocity is 10π rad/sec
step 1
convert to rad/min
1 min-----60 sec
X min----> 1 sec
X=1/60 min
V=</span>10π rad/(1/60)------> V=600 π rad/min

the answer is the option 
<span>D)The angular velocity is 600π rad/min.</span>
6 0
2 years ago
Read 2 more answers
Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

8 0
2 years ago
Please help me out with this
vichka [17]

Answer:

25

Step-by-step explanation:

sin © =36/(35+x)=21/35

36/(35+x)=21/35

x=(36*35/21)-35

x=25

3 0
1 year ago
Read 2 more answers
Elena went on a 6-mile walk. She completed the first half of the walk 1 mi/h faster than usual and the second half of the walk 2
xxTIMURxx [149]

Answer:

Her usual rate is 0.8333 miles per hour.

Step-by-step explanation:

The velocity formula is given by:

v = \frac{d}{t}

In which d is the distance and t is the time.

She completed the first half of the walk 1 mi/h faster than usual

Her usual rate is v. 1mph faster is v + 1.

The second half of the walk 2 mi/h slower than the first half.

The first half is v + 1.

2mph slower is v + 1 - 2 = v - 1. Then

Total rate:

7.2 hours, and 6 miles. So

One half is v+1 and the other is v - 1. This is why each is multiplied by 0.5.

0.5(v + 1) + 0.5(v - 1) = \frac{6}{7.2}

0.5v + 0.5 + 0.5v - 0.5 = 0.8333

v = 0.8333

Her usual rate is 0.8333 miles per hour.

8 0
2 years ago
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