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barxatty [35]
3 years ago
12

Simplify the following problem.

Mathematics
1 answer:
natima [27]3 years ago
7 0

Answer: I think the answer is c

Step-by-step explanation:

tell me if im wrong :(

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Please help....What is a problem that makes sense for this question? ASAP!!
ddd [48]

Explanation:

250 can be used as a total, with 10 being how much something subtracted multiple times takes away, and 20 being the end result. So, we could make the problem about a lot of things, but I'll go ahead and write the first one that comes to mind.

Answer:

Arata has $250 in his bank account, and plans on buying several CDs. Each one costs $10, and by the end of the trip, there is only $20 left in his account. How many CDs did Arata buy, assuming there was no tax or other additional charges?

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4 years ago
Please help!!!!!<br> Please
Dimas [21]
So you just multiply 48 by 2 then by 3 and then by 4 resulting to a=96, b=144, c=192
7 0
3 years ago
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I’m not exactly sure how to do this precalc problem.
Veronika [31]

Step-by-step explanation:

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5 0
3 years ago
P is a prime number and q is a positive integers such that p + q = 1696 IF P and Q are co primes and their Lcm is 21879 Then fin
Stolb23 [73]

Answer:

P = 1 3  

Q = 1 6 8 3

Step-by-step explanation:

through factorization of 21879

4 0
3 years ago
***********BRAINLIEST IF 2 PPL ANSWER*******Thank u!!!
Elden [556K]

Problem 1

Answer: year 4

---------------------

The break-even point is when the profit is $0. You neither earn money nor lose it.

Plug in p(x) = 0 and solve for x

p(x) = x^3 - 4x^2 + 5x - 20

x^3 - 4x^2 + 5x - 20 = p(x)

x^3 - 4x^2 + 5x - 20 = 0 ... replace p(x) with 0

(x^3 - 4x^2) + (5x - 20) = 0

x^2(x - 4) + 5(x - 4) = 0

(x^2+5)(x - 4) = 0

x^2+5 = 0 or x-4 = 0

The equation x^2+5 = 0 has no real solutions; however x-4 = 0 solves to x = 4.

So plugging x = 4 into p(x) will lead to p(x) = 0. Meaning that the company breaks even at year 4.

==========================================================

Problem 2

Answer: choice B) between 2.5 and 3.0; between 4.0 and 4.5

---------------------

Look at the f(x) column. Specifically we are looking for the times when the numbers change from positive to negative, or vice versa. Somewhere in between this change, y will have to equal 0 at some point (at least once). Note how in row 2 and row 3, we have f(x) = 1.1 change to f(x) = -0.8; so the change is from positive to negative.

This means f(x) = 0 for some x value between x = 2.5 and x = 3.5. Also, the same kind of logic applies for the last two rows of the table as well pointing to another root between x = 4.0 and x = 4.5 (check out the attached images)


5 0
3 years ago
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