A number decreased by three square is: (where x is the number)
x - 3^2
Answer:
t=3.5 seconds
Step-by-step explanation:
Given
h(t) = −16t^2 + 111t + 0
h'(t)= -32t + 111
Maximum height occurs when h(t) = 0 and the ball begins to fall
h(t)= -32t + 111=0
-32t + 111=0
-32t=-111
Divide both sides by -32
t=3.46872
Approximately, t=3.5 seconds
Recall,
Maximum height occurs when h(t) = 0
h(t)= -32t + 111=0
= -32(3.46872)+111
= -110.99904+111
= 0.00096 ft
Y=mx+b
m=slope
paralell ines have same slope
y=2/3x-6
slope is 2/3
the equation of aline that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
given
(3,14) and slope is 2/3
y-14=2/3(x-3)
y-14=2/3x-2
y=2/3x+12
