Evaluate the determinant for the following matrix [3 -5 / 1 1]

Mathematics

1 answer:

Natalka [10]3 years ago

6 0

Answer:

Step-by-step explanation:

$\det\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =ad-bc\\\\\det\left[\begin{array}{ccc}3&-5\\1&1\end{array}\right] =(3)(1)+(-5)(1)=3-5=-2$

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At the beginning of a snowstorm, Nathaniel had 5 inches of snow on his lawn.

vivado [14]

Answer:

In 5 hours he would have 7.5 inches of snow JUST from the snowstorm but the question says that he already had 5 inches in his lawn so that would make 12.5 inches of snow in 5 hours.

The second one says t, it doesn't state a number so lets assume the number is ten. So that's 5 more hours of constant snowfall, this makes our total be the sum of 12.5+7.5. This is equal to 20.

10 hours into the snowstorm Nathaniel had 20 inches of snow in his lawn.

Consider a brainliest if it helps :)

3 0

3 years ago

Read 2 more answers

Can someone help me? this is extremely important for me to complete!

Nataliya [291]

Answer:

Question 1: A,B,D,F

Queation2: the order is 2,3,1

Question3:A

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Step-by-step explanation:

8 0

3 years ago

If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?

melamori03 [73]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4432.37\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &8
\end{cases}$

$\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8
\\\\\\
\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r
\\\\\\
0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086
\\\\\\
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3 years ago

Can u help me with this

Nesterboy [21]

A graphing calculator is a great help for problems of this nature.
x ∈ {-5.63, -0.55, 2.59}