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1 year ago

A decimal that is equal to the fraction 3/5?

Mathematics

2 answers:

AVprozaik [17]1 year ago

7 0

Answer:

0.6

Step-by-step explanation:

aleksandrvk [35]1 year ago

5 0

Answer:

0.6

Step-by-step explanation:

i hope this helps! have a wonderful rest of ur day :)

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Evaluate: <img src="https://tex.z-dn.net/?f=3-2%5E2%2B4%2A3%2B5" id="TexFormula1" title="3-2^2+4*3+5" alt="3-2^2+4*3+5" align="a

earnstyle [38]

Answer:

Step-by-step explanation:

Apply PEMDAS:

Solve the exponent, multiply from left to right, and then subtract and add from left to right.

$3-2^2+4*3+5\\\\3-4+4*3+5\\\\3-4+12+5\\\\-1+12+5\\\\11+5\\\\\boxed{16}$

8 0

2 years ago

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HELPPPPP!!!!!!!!!!!!!!

zhenek [66]

Answer

0.75 or 3/4 is the answer (degree)

I just solved for the angles and use a graphing calculator to find the din and cosine values and multiply them

5 0

2 years ago

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Find the height of a square pyramid that has a volume of 12 cubic feet and a base length of 3 feet

Andreyy89

I got the height to be 4

8 0

2 years ago

Solve the equation for x.

ivann1987 [24]

Answer:

x = 44

Step-by-step explanation:

sqrt(x+5) -3 =4

Add 3 to each side

sqrt(x+5) -3+3 =4+3

sqrt(x+5) =7

Square each side

(sqrt(x+5))^2 =7^2

x+5 = 49

Subtract 5 from each side

x+5-5 = 49-5

x=44

3 0

2 years ago

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The midpoint of UV is point W. What are the coordinates of point V?

madreJ [45]

Since you don't provide the coordinates of the point W, I will help you in a general form anyway. In the Figure below is represented the segment that matches this problem. We have two endpoints U and V. So, by using the midpoint formula we may solve this problem:

$Midpoint=W=W(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})=W(x_{3}, y_{3}) \\ \\ where:\\ \ U=U(x_{1}, y_{1}) \ and \ V=V(x_{2}, y_{2}) \\ \\ and: \\ x_{3}=\frac{x_{1}+x_{2}}{2} \\ y_{3}=\frac{y_{1}+y_{2}}{2}$

Therefore:

$x_{2}=2x_{3}-x_{1} \\ y_{2}=2y_{3}-y_{1}$

So we know $x_{3} \ and \ y_{3}$ but we also must know $x_{1} \ and \ y_{1}$

Finally, knowing the points U and W we can find the endpoint V.

7 0

2 years ago

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