-x=-y+2
x=y-2
now substitute iin the first one
y=(y-2)^2+5 (y-2)-3
y=y^2-4y+4 +5y-10-3
y=y^2+y-9
y^2-9=0.
y^2=9
y=3
3-x=2
-x=2-3
-x=-1
x=1
the solution are x=1 and y=3
3=1^2+5 (1)-3
3=1+5-3
3=6-3
3=3
Let x+500 represent the first year
For the $500 more than the previous year for 4 years, we would write:
(x+500)+(x+500+500+500)+(x+500+500+500+500)= 17,800
By adding the equation above, 4x+5000=17,800
4x=17,800-5000
4x=12,800
x=3,200
So the amount the man was paid in the first year is 3,200+500=3,700
x=−2x=-2 (Multiplicity of 22)
x=4x=4 (Multiplicity of 11)
Answer:
Step-by-step explanation:
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Answer: 40 PLEASE MARK BRAINLEST
Step-by-step explanation: