Question

the lengths of the sides of a triangle are consecutive odd integers.if the perimeter of the triangle is 27 what is are the lengths of all three sides?

Answer 1

Bearing in mind that, if you multiply any integer whatsoever, by 2, you get an even number, 3*2 or 17*2 or 4*2 and so on.

to get an ODD integer, simply hop once forward of backwards from any even integer, 2-1, or 2+1 or  8+1 or 8-1.

to get a consecutive ODD integer, simply hop twice from any odd integer, say 3+2, or 7+2 and so on.

now, let's pick a reference integer, say hmmm "a".

we know that a * 2, or 2a is an even integer, therefore (2a + 1) is an ODD integer, and (2a +1 ) + 2 is a consecutive odd integer.  So, there you have it, our first two odd integers, and the next one, is, you guessed it, (2a + 1) + 2 + 2

so, our three odd consecutive integers are (2a+1), (2a+3) and (2a+5)

so, the triangle has a perimeter of 27, so, let's add them up then

$\bf (2a+1)+(2a+3)+(2a+5)=27\implies 6a+9=27 \\\\\\ 6a=18\implies a=\cfrac{18}{6}\implies a=3$

so, our first odd integer is

2a + 1

2(3) + 1 --> 7

and surely you know what the other two are.

Answer 2

The lengths of each side are 9