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attashe74 [19]
3 years ago
9

50 US states for the namethat start with the letter W what percent of US states have the names that start with the letter W

Mathematics
1 answer:
Vanyuwa [196]3 years ago
3 0
Washington, West Virginia, Wisconsin, Wyoming
Four states out of 50
4 / 50 * 100 = 8 per cent.


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5) One restaurant charges $7 per person and $1 admission fee. A second compant Charges $5 per
Assoli18 [71]

The people will there need to be in order for the second company to be less expensive in 1st restaurant.

Always assume the unknowns are variables when attempting to find them, and then construct the equation using the parameters specified in the question.

Admission fee for 1st restaurant = $1

Charge for 1st restaurant per person = $7

Admission fee for 2nd restaurant = $15

The number of employees required for 2nd restaurant need to have in order to be less expensive = x

Total amount needed for 1st restaurant = $1 + $7 = $8

To make the 2nd restaurant less expensive =

As the total amount of 1st restaurant is $8 and the admission fee 2nd restaurant itself is $15 2nd restaurant is more expensive than the 1st one.

To learn more about Word problems related to arithmetic operation from the link:

brainly.com/question/24464054

#SPJ9

5 0
1 year ago
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
Please solve equations by completing square
BlackZzzverrR [31]
x^2-4x+1=0\\
x^2-4x+4-3=0\\
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x-2=\sqrt3 \vee x-2=-\sqrt3\\
x=2+\sqrt3 \vee x=2-\sqrt3

x^2+6x-9=0\\
x^2+6x+9-18=0\\
(x+3)^2=18\\
|x+3|=\sqrt{18}=3\sqrt2\\
x+3=3\sqrt2 \vee x+3=-3\sqrt2\\
x=-3+3\sqrt2 \vee x=-3-3\sqrt2\\

x^2+20x+3=0\\
x^2+20x+100-97=0\\
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x=-10+\sqrt{97} \vee x=-10-\sqrt{97}

x^2-2x-5=0\\
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8 0
3 years ago
Triangle BAC was rotated 90° clockwise and dilated at a scale factor of 2 from the origin to create triangle XYZ. Based on these
ololo11 [35]

Answer:b=x

Step-by-step explanation:

8 0
2 years ago
80Divided by 3 plz help
mojhsa [17]

Answer:

Your answer is 26.667

hope this helps

8 0
2 years ago
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