In my opinion, Darrin's inference is wrong because according to given question, "<em>Darrin surveyed a random sample of 10 students from his science class about their favorite types of TV shows.</em><em>"</em><em> </em>
This line provides the information that the survey is taken randomly. Also, if Darrin had taken some other students, then the ineference of other new students compared with previously surveyed students will be different.
This frankly tells that <em>t</em><em>h</em><em>e</em><em> </em><em>p</em><em>r</em><em>o</em><em>b</em><em>a</em><em>b</em><em>i</em><em>l</em><em>i</em><em>t</em><em>y</em><em> </em><em>i</em><em>s</em><em> </em><em>d</em><em>i</em><em>f</em><em>f</em><em>e</em><em>r</em><em>e</em><em>n</em><em>t</em><em> </em><em>a</em><em>l</em><em>w</em><em>a</em><em>y</em><em>s</em><em>.</em>
Therefore, Darrin's inference is wrong or invalid.
Answer: 904.78 cu. ft
Step-by-step explanation:
Volume of sphere = 4/3 pi r^3
Assuming 12 ft. is the diameter of the sphere.
Answer:
The position P is:
ft <u><em> Remember that the position is a vector. Observe the attached image</em></u>
Step-by-step explanation:
The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity
is:

Where
is the initial height = 0 for this case
We know that the initial velocity is:
82 ft/sec at an angle of 58 ° with respect to the ground.
So:
ft/sec
ft/sec
Thus

The height after 2 sec is:


Then the equation that describes the horizontal position of the ball is

Where
for this case
ft / sec
ft/sec
So

After 2 seconds the horizontal distance reached by the ball is:

Finally the vector position P is:
ft
First term is -7, so a_1 = -7
To get the next term, we add on 4. We can see this if we subtract like so
d = (2nd term) - (1st term) = (-3) - (-7) = -3+7 = 4
So d = 4 is the common difference.
Apply a_1 = -7 and d = 4 to get...
a_n = a_1 + d*(n-1)
a_n = -7 + 4*(n-1)
a_n = -7 + (n-1)*4
Answer: Choice A