Let u = 4x^2, then y=e^u
dy/dx= dy/du x du/dx
dy/dx= 8xe^4x^2
Then do product rule to find d2y/dx2
d2y/dx2 = 64 x^2 e^4x^2 + 8e^4x^2
Substitute d2y/dx2 and dy/dx into the equation then will get equal to zero

4 0

3 years ago

One number has three significant figures and another number has four significant figures. If these numbers are added, subtracted

d1i1m1o1n [39]

Answer:

Addition

Step-by step explanation:

Let a=5.54 and b=5.566

a+b=5.54+5.566=11.106

Using significant rule of addition

a+b=11.11(4 significant figures)

b-a= 0.026

Using significant rule of subtraction

b-a=0.03(Two significant figures)

$a\times b=5.54\times 5.566= 30.83564$

Using significant rule of multiplication

$a\times b=30.8$ (3 significant figures)

$\frac{b}{a}=\frac{5.566}{5.54}=1.00469$

Using significant rule of division

$\frac{b}{a}=1.00$ (Three significant figures)

Addition can produce the greatest number of significant figures

4 0

3 years ago