* J,K,&L are coplanar
* K is the midpoint of JL
* J,K,&L are collinear
* Jk=KL
Answer:
( cos40° + isin40°)
Step-by-step explanation:
To divide
![\frac{r_{1(cosx_{1}+isinx_{1}) } }{r_{2}(cosx_{2}+isinx_{2}) }](https://tex.z-dn.net/?f=%5Cfrac%7Br_%7B1%28cosx_%7B1%7D%2Bisinx_%7B1%7D%29%20%20%7D%20%7D%7Br_%7B2%7D%28cosx_%7B2%7D%2Bisinx_%7B2%7D%29%20%20%20%7D)
=
[ cos(x₁ - x₂) + isin(x₁ - x₂)
Given
![\frac{2(cos90+isin90}{4(cos50+isin50)}](https://tex.z-dn.net/?f=%5Cfrac%7B2%28cos90%2Bisin90%7D%7B4%28cos50%2Bisin50%29%7D)
=
( cos(90 - 50)° + isin(90 - 50)°
=
( cos40° + isin40° )
Answer:
A reflection across the y- axis
Step-by-step explanation:
Under a reflection in the y- axis
a point (x, y) → (-x, y)
A point in the second quadrant (- x, y)
Under reflection in the y- axis is (x, y) ← point in first quadrant
You would have to Find the GCF
20m ^2
Explanation:
The top part be be cut into 2 2•2 triangles. A = 4 for both of them
And the rest is a 4•4 square, so A = 16.
4 + 16 = 20
Hope this helps!