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Elodia [21]
3 years ago
10

How to solve an equation with two different variables.

Mathematics
1 answer:
77julia77 [94]3 years ago
7 0

Answer:

Step-by-step explanation:

Move the variables to different sides of the equation. This "substitution" metho d starts out by "solving for x" (or any other variable) in one of the ...

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5.476 rounded to the hundredths place
Murrr4er [49]
5.476 rounded to the hundredths place = 5.48
5 0
4 years ago
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A “stick” object of height 10 cm is standing in front of a point X–ray source at a distance of 50 cm from the source. The detect
blagie [28]

Answer:

40 cm.

Step-by-step explanation:

Given,

height of the object = 10 cm

Distance of the object from the X-ray= 50 cm

Distance of detector from the source = 2 m = 200 cm

Height of the image, h = ?

Now,

\tan \theta = \frac{P}{B}

\tan \theta = \frac{10}{50}

\tan \theta = \frac{1}{5}

Again applying

\tan \theta = \frac{P}{B}

\frac{1}{5} = \frac{h}{200}

h = 40 cm

Hence, height of the image is equal to 40 cm.

6 0
3 years ago
How many different triangles can be made with the angles 45 degree, 45 degree, 90degree ?
pychu [463]

Answer:

C: one triangle

Step-by-step explanation:

well a triangle = 180°

45+45=90

90+90=180

7 0
3 years ago
Read 2 more answers
Find the surface area of this net.
Elden [556K]

Answer:

<h2>231cm²</h2>

Step-by-step explanation:

First, let's find the surface area of both the triangles

5x3=15

So, the surface area of the triangles is 15 sq.cm

Now, let's find the surface area of the base (large rectangle in the middle)

12x8=?

10x8=80

2x8=16

80+16=96

12x8=96

So, the surface area of the base, is 96sq.cm

Now, let's find the surface area of both of the side rectangles

12x5=60

60x2=120

So, the surface area of the two side rectangles is 120sq.cm

Now, let's find the total surface area by adding all of our answers.

120+96=216

216+15=231

<h2>So hence, the surface area of this net is 231cm²</h2>
3 0
2 years ago
if a right circular cone has a volume of 15 cubic ft and a radius of 3 ft, what is the height of the cone?
Setler79 [48]
Volume of cone=1/3 times height times pir^2
v=15
r=3
15=1/3 hpi3^2
15=1/3hpi9
15=9/3hpi
15=3hpi
divide 3
5=hpi
h=5/pi
pi=aprox 3.14
5/3.14=1.59

1.59 ft
4 0
3 years ago
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