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AleksandrR [38]

3 years ago

5

Lucy si thinking of a Numbers. The number is greater than two hundred twenty-five. Her number is less than 2 hundreds,2 tens, an

d 7 ones. What is Lucy's number?

1 answer:

VikaD [51]3 years ago

8 0

226 i believe, if not then idk

You might be interested in

∆ABC has vertices A(–2, 0), B(0, 8), and C(4, 2)

Natali [406]

Answer:

Part 1) The equation of the perpendicular bisector side AB is $y=-\frac{1}{4}x+\frac{15}{4}$

Part 2) The equation of the perpendicular bisector side BC is $y=\frac{2}{3}x+\frac{11}{3}$

Part 3) The equation of the perpendicular bisector side AC is $y=-3x+4$

Part 4) The coordinates of the point P(0.091,3.727)

Step-by-step explanation:

Part 1) Find the equation of the perpendicular bisector side AB

we have

A(–2, 0), B(0, 8)

<em>step 1</em>

Find the slope AB

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{8-0}{0+2}$

$m=4$

<em>step 2</em>

Find the slope of the perpendicular line to side AB

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

therefore

The slope is equal to

$m=-\frac{1}{4}$

<em>step 3</em>

Find the midpoint AB

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

substitute the values

$M(\frac{-2+0}{2},\frac{0+8}{2})$

$M(-1,4)$

<em>step 4</em>

Find the equation of the perpendicular bisectors of AB

the slope is $m=-\frac{1}{4}$

passes through the point $(-1,4)$

The equation in slope intercept form is equal to

$y=mx+b$

substitute

$4=(-\frac{1}{4})(-1)+b$

solve for b

$b=4-\frac{1}{4}$

$b=\frac{15}{4}$

so

$y=-\frac{1}{4}x+\frac{15}{4}$

Part 2) Find the equation of the perpendicular bisector side BC

we have

B(0, 8) and C(4, 2)

<em>step 1</em>

Find the slope BC

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{2-8}{4-0}$

$m=-\frac{3}{2}$

<em>step 2</em>

Find the slope of the perpendicular line to side BC

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

therefore

The slope is equal to

$m=\frac{2}{3}$

<em>step 3</em>

Find the midpoint BC

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

substitute the values

$M(\frac{0+4}{2},\frac{8+2}{2})$

$M(2,5)$

<em>step 4</em>

Find the equation of the perpendicular bisectors of BC

the slope is $m=\frac{2}{3}$

passes through the point $(2,5)$

The equation in slope intercept form is equal to

$y=mx+b$

substitute

$5=(\frac{2}{3})(2)+b$

solve for b

$b=5-\frac{4}{3}$

$b=\frac{11}{3}$

so

$y=\frac{2}{3}x+\frac{11}{3}$

Part 3) Find the equation of the perpendicular bisector side AC

we have

A(–2, 0) and C(4, 2)

<em>step 1</em>

Find the slope AC

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{2-0}{4+2}$

$m=\frac{1}{3}$

<em>step 2</em>

Find the slope of the perpendicular line to side AC

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

therefore

The slope is equal to

$m=-3$

<em>step 3</em>

Find the midpoint AC

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

substitute the values

$M(\frac{-2+4}{2},\frac{0+2}{2})$

$M(1,1)$

<em>step 4</em>

Find the equation of the perpendicular bisectors of AC

the slope is $m=-3$

passes through the point $(1,1)$

The equation in slope intercept form is equal to

$y=mx+b$

substitute

$1=(-3)(1)+b$

solve for b

$b=1+3$

$b=4$

so

$y=-3x+4$

Part 4) Find the coordinates of the point of concurrency of the perpendicular bisectors (P)

we know that

The point of concurrency of the perpendicular bisectors is called the circumcenter.

Solve by graphing

using a graphing tool

the point of concurrency of the perpendicular bisectors is P(0.091,3.727)

see the attached figure

5 0

2 years ago

Determine whether the equation y-y=y is sometimes,always, or never true?

beks73 [17]

The answer is it is yes, it is sometimes true, y can =0

6 0

3 years ago

Which of the equations below could be the equation of this parabola? A y = 1/6x2 B. x = -1/6y2 C. x = 1/6y2 D. y = -1/6x2

Schach [20]

Answer:

C

Step-by-step explanation:

assuming the 2s are all squares

just plot a point and it's negative

7 0

2 years ago

PLS HELP ME PLS SOVLE THIS WITH THE LIKE TERMS I ONLY HAVE 25 MINS TO FINISH THIS

Basile [38]

Answer:

Step-by-step explanation:

Here are the 3 answers you needed :)!!!

8 0

3 years ago

Read 2 more answers

The width of a rectangle is six meters less than three times its length. If the area of the rectangle is 105 square meters. what

Kipish [7]

Answer:

length = 7 meters

Step-by-step explanation:

l = length

w = width

w = 3×l - 6

l×w = 105 m²

l×(3×l - 6) = 105

3×l² - 6×l = 105

l² - 2×l = 35

l² - 2×l - 35 = 0

solution of a squared equation is

(-b ± sqrt(b² - 4ac))/(2a)

a = 1

b = -2

c = -35

(2 ± sqrt(4 - 4×-35))/2 = (2 ± sqrt(4+140))/2 =

(2 ± sqrt(144))/2 = (2 ± 12)/2 = 1 ± 6

l1 = 1+6 = 7 meters

l2 = 1-6 = -5 meters, which did not make any sense for an actual object.

so, l = 7 meters remains.

7 0

2 years ago