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BARSIC [14]
3 years ago
15

The vertex of this parabola is at (3, -2). When the x-value is 4, the y-value is 3. What is the coefficient of the squared expre

ssion in the parabola's equation?
Mathematics
2 answers:
user100 [1]3 years ago
5 0
Hello :
<span>the parabola's equation is : f(x) = a(x-3)²-2
</span><span>the coefficient of the squared expression in the parabola's equation is : a
but ; f(4) = 3
3 = a(4-3)²-2
a-2=3.....a=5
f(x) = 5(x-3)²-2</span>
neonofarm [45]3 years ago
3 0

Answer:

5

Step-by-step explanation:

I answered the question and got it right

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What is 92 divided by 2?
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46. Fortysix times 2 equals 92.
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ECA is a semi equilateral triangle at C,
stiks02 [169]

Answer: its 50

Step-by-step explanation:

6 0
1 year ago
Consider the line y=9x-5.
igomit [66]
Y = 9x - 5...the slope here is 9...a parallel line will have the same slope.

y = mx + b
slope(m) = 9
(5,-4)...x = 5 and y = -4
now we sub and solve for b, the y int
-4 = 9(5) + b
-4 = 45 + b
-4 - 45 = b
-49 = b
so ur parallel line is : y = 9x - 49

y = 9x - 5...slope is 9. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -1/9.

y = mx + b
slope(m) = -1/9
(5,-4)...x = 5 and y = -4
now we sub and solve for b, the y int
-4 = -1/9(5) + b
-4 = -5/9 + b
-4 + 5/9 = b
-36/9 + 5/9 = b
- 31/9 = b

so ur perpendicular line is : y = -1/9x - 31/9

6 0
3 years ago
∆ABC is similar to ∆PQR. AB¯¯¯¯¯ corresponds to PQ¯¯¯¯¯, and BC¯¯¯¯¯ corresponds to QR¯¯¯¯¯. If the length of AB¯¯¯¯¯ is 9 units
wel
The first blank is propyl 4 and the second is 2 (this is what I can tell if AB was 9 then PQ 3, so practically dividing by 3)
8 0
3 years ago
Read 2 more answers
The angle bisectors of AXYZ are XG, YG, and ZG. They meet at a single point G.
Harrizon [31]

Answer:

m∠FXD = 36°

EG = 10

m∠FZG = 24°

Step-by-step explanation:

In triangle XYZ, G is the incenter of the triangle.

Since, m∠FXG = 18°

And m∠FXD = 2(m∠FXG)

                     = 2 × 18°

                     = 36°

Since, point G is equidistant from all sides (Property of incenter of a triangle)

Therefore, DG = EG = GF = 10

Since, m∠X + m∠Y + m∠Z = 180°

2(m∠FXG) + m∠DYE + 2(m∠FZG) = 180°

2(18)° + 96° + 2(m∠FZG) = 180°

2(m∠FZG) = 180° - 132°

m∠FZG = 24°

3 0
3 years ago
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