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Evgesh-ka [11]
3 years ago
13

2/4 - 2/7 in simplest form

Mathematics
1 answer:
prisoha [69]3 years ago
7 0

2/4  = 1/2  

1/2 - 2/7   LCD of 2 and 7 is 14

7/14 - 4/14  = 3/14   

thats the answer
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How come eleven times eleven equal 121
sasho [114]
Try adding 11, 11 times. It is a long process, but it should give you what you are looking for. First. to break it down add 10 eleven time, then after you get 110 add the remaining 11.
8 0
3 years ago
15pts<br> f(x)=(x+6)/2<br> g(x)=2x - 6<br> Show your work to evaluate g(f(x)).
notsponge [240]

Answer:

g(f(x)) = -x - 18

Step-by-step explanation:

2x - 6( (x + 6) / (2) )

2x - 3( x + 6)

2x - 3x - 18

-x - 18

4 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
3 years ago
10, 30, 90 continue the pattern
Novosadov [1.4K]
The answer is 270, the pattern is multiplying by 3. So, 10 • 3 = 30 30 • 3 = 90 90 • 3 = 270, and so on. Hope this helps! Let me know if you need any further assistant.
7 0
2 years ago
Read 2 more answers
Write 0.25 as a fraction
Anarel [89]
25/100 also 1/4
they are the same fraction, one of them is just simplified
4 0
2 years ago
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