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3 years ago

The slope of a line is 1/3. What is the slope of a line perpendicular to this line?

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

3 0

A perpendicular line has a negative reciprocal of a given line.

The given slope is 1/3, the reciprocal of this would be 3/1, which simplifies to 3.

The negative of 3 is -3.

The answer is a) -3.

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On a 2,000 calorie diet, how many calories would come from VEGGIES? *

GREYUIT [131]

700 cal out of the 2000
2000*.35

8 0

2 years ago

2 = f/8 f= ? Pleaze helpsz me i will give you robux I promise !!

Ilia_Sergeevich [38]

Answer:

f = 16

Step-by-step explanation:

2 = f/8

Cross Multiplying, we get

f = 16

hope it helps!

8 0

2 years ago

Read 2 more answers

PLEASE HELP LAST QUESTION

igomit [66]

ANSWER:

a) y = 15x + 75

b) 50 weeks

EXPLANATION:

P A R T A

2 weeks, 105 dollars --> (2, 105)

5 weeks, 150 dollars --> (5, 150)

if we use slope intercept form (y=mx+b), we must:

1) find the slope

y2 - y1 -->> 150 - 105 = 45

x2 - x1 -->> 5 - 2 = 3

45/3 = 15

2) find the y intercept

y = 15x + b -->> 150 = 15 (5) + b -->> 150 = 75 + b -->> 75 = b

--------------------------------------------------------------------------------------------

P A R T B

y = 15x + 75 (substitute the y with 825 because that is the goal)

825 = 15x + 75 (solve normally)

750 = 15x

50 = x

5 0

2 years ago

Solution of the equation 3x/5+1=4x/15+7

Anika [276]

Answer:

x = 18

Step-by-step explanation:

Given

$\frac{3x}{5}$ + 1 = $\frac{4x}{15}$ + 7 ( subtract 1 from both sides )

$\frac{3x}{5}$ = $\frac{4x}{15}$ + 6

Multiply through by 15 to clear the fractions

9x = 4x + 90 ( subtract 4x from both sides )

5x = 90 ( divide both sides by 5 )

x = 18

4 0

2 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second