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Hoochie [10]
3 years ago
5

What is an equation of the line that passes through the points (3, -3) and (6, -1)?​

Mathematics
1 answer:
ladessa [460]3 years ago
3 0
Start by finding the slope using m = (y2 - y1)/(x2 - x1). Substituting in you get (-1 + 3)/(6 - 3). So m = 2/3

Next, use y - y1 = m(x - x1) and substitute any of the coordinates in: y + 3 = 2/3(x - 3). That gives you y + 3 = (2/3)x - 2. So tha final answer is y = (2/3)x -5
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I believe x is equal to 23
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Evaluate the expression, xz- y, if x=3,y=6, and z =7
avanturin [10]
3*7-6
21-6=15
15 is the answer
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2 years ago
ILL GIVE BRAINLIEST ! Need help with algebra. random answers get reported.
Alex_Xolod [135]

Answer:

1.2.4

2. -8

3. -5-3

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5.-10-3

6. 2+2=4

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2 years ago
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Find the x- and y- intercepts of the line with the given equation <br><br> -6x+8y=-36
Likurg_2 [28]

Answer:

Y int at

(

0

,

3

2

)

X int at

(

3

,

0

)

Step-by-step explanation:

The line is easier to visualize when the equation is in slope-intercept form:

4

x

+

8

y

=

12

Divide each side by 4:

x

+

2

y

=

3

2

y

=

−

x

+

3

y

=

−

1

2

x

+

3

2

Y-intercept (plug in 0 for x):

y

=

−

1

2

(

0

)

+

3

2

y

=

3

2

X-intercept (plug in 0 for y):

0

=

−

1

2

x

+

3

2

−

3

2

=

−

1

2

x

x

=

3

5 0
3 years ago
Read 2 more answers
The sum of squares of two
Elanso [62]

Answer:

the product of the 2 numbers is 22

Step-by-step explanation:

x² + y² = 80

(x - y)² = 36

=>

x - y = 6

or y - x = 6

let's start with the first one x-y=6

x = 6 + y

=>

(6+y)² + y² = 80

y² + 6y +6y + 36 + y² = 80

2y² + 12y + 36 = 80

2y² + 12y - 44 = 0

y² + 6y - 22 = 0

the solution of a quadratic equation

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case here we have an squadron in y.

a=1

b=6

c=-22

(-6 ± sqrt(36 + 4×22))/2 = (-6 ± sqrt(36+88))/2 =

= (-6 ± sqrt(124))/2 = (-6 ± sqrt(4×31))/2 =

= (-6 ± 2×sqrt(31))/2 = -3 ± sqrt(31)

y1 = -3 + sqrt(31)

y2 = -3 - sqrt(31)

=>

x1 = 6 + -3 + sqrt(31) = 3 + sqrt(31)

x2 = 3 - sqrt(31)

control :

(-3 + sqrt(31))² + (3 + sqrt(31))² = 80

9 - 3 sqrt(31) - 3 sqrt(31) + 31 + 9 +3 sqrt(31) + 3 sqrt(31) + 31 = 80

9 + 31 + 9 +31 = 80

18 + 62 = 80

80 = 80 correct

solving now for y-x=6

delivers exactly the same calculations, just with x and y trading places.

so, the resulting 2 number pairs are the same.

the product of the 2 numbers :

(3 + sqrt(31))(-3 + sqrt(31)) = -9 - 3 sqrt(31) + 3 sqrt(31) + 31 =

= -9 + 31 = 22

(3 - sqrt(31))(-3 - sqrt(31)) = -9 + 3 sqrt(31) - 3 sqrt(31) + 31 =

= 22

so, the product is the same in both cases.

6 0
2 years ago
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