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k0ka [10]
3 years ago
8

With the ratio at 1:1, Point C appears to be the midpoint. Use the midpoint formula to ascertain (make sure of) whether Point C

is at the midpoint. Explain how the ratio 1:1 would place Point C at the midpoint of AB.
Mathematics
1 answer:
Mila [183]3 years ago
4 0

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete because the coordinates of A, B and C were not given in the question.

However, the following explanation will guide you...

The midpoints, C of two point A and B is calculated as:

C(x,y) = (\frac{x_1 + y_1}{2}, \frac{y_1 + y_2}{2})

Where (x_1, y_1) are the coordinates of A

and

(x_2,y_2) are the coordinates of B

Take for instance, the given coordinates are

A(4,6); B(2,4) and C(3,5)

Then;

Plug in these values in the given formula:

C(x,y) = (\frac{x_1 + y_1}{2}, \frac{y_1 + y_2}{2})

(3,5) = (\frac{4 + 2}{2}, \frac{6 + 4}{2})

(3,5) = (\frac{6}{2}, \frac{10}{2})

(3,5) = (3,5)

In that case,

C is really the midpoint

To the b part: <em>Explaining why ratio 1:1 is used</em>

The reason is that both parts of the ratio are in equal proportion (1 and 1);

Because of this equal proportion, ration 1:1 is right to calculate the midpoint

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Answer:

Step-by-step explanation:

The question is slightly ambiguous. The problem is, do you find the first 40 hours using 10x and then the second equation using x >40. I don't think so, but it should be made clear. It turns out that the first 40 hours does equal 400 so that you can use the second expression with no worries.

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SCORPION-xisa [38]
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Answer:  (x+2)^2+3\\\\

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==================================================

Explanation:

Let's expand out (x+a)^2+b to get the following:

(x+a)^2+b\\\\(x+a)(x+a)+b\\\\x(x+a)+a(x+a)+b\\\\x^2+ax+ax+a^2+b\\\\x^2+2ax+a^2+b\\\\

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Compare this to the x term of x^2+4x+7 and we see that

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--------------

The constant term of x^2+2ax+a^2+b\\\\ is the a^2+b portion since it doesn't have the variable x attached to it.

Compare this with the 7 of x^2+4x+7 which is also the constant.

Equate the two items, plug in a = 2 and solve for b.

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Therefore,

x^2+4x+7 = (x+a)^2+b\\\\x^2+4x+7 = (x+2)^2+3\\\\

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$4 dollars. My process was first, creating the matrix. 

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