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2 years ago

I RLLY NEED HELP PLS!!

Mathematics

1 answer:

lara [203]2 years ago

5 0

Answer: $(x+2)^2+3\\\\$

a = 2 and b = 3

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Explanation:

Let's expand out $(x+a)^2+b$ to get the following:

$(x+a)^2+b\\\\(x+a)(x+a)+b\\\\x(x+a)+a(x+a)+b\\\\x^2+ax+ax+a^2+b\\\\x^2+2ax+a^2+b\\\\$

The x term here is 2ax

Compare this to the x term of $x^2+4x+7$ and we see that

$2ax = 4x\\\\2a = 4\\\\a = 4/2\\\\a = 2\\\\$

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The constant term of $x^2+2ax+a^2+b\\\\$ is the $a^2+b$ portion since it doesn't have the variable x attached to it.

Compare this with the 7 of $x^2+4x+7$ which is also the constant.

Equate the two items, plug in a = 2 and solve for b.

$a^2+b = 7\\\\2^2+b = 7\\\\4+b = 7\\\\b = 7-4\\\\b = 3\\\\$

Therefore,

$x^2+4x+7 = (x+a)^2+b\\\\x^2+4x+7 = (x+2)^2+3\\\\$

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Inverse of f(x) = 3 + 2 In x?

JulsSmile [24]

This is the inverse of f(x)= -3 - (-2)

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3 years ago

Please need help with this math question

Tomtit [17]

Answer:

third option

Step-by-step explanation:

We just have to calculate 2x² - 4x - (x² + 6x). 2x² - x² = x² and -4x - 6x = -10x so the answer is x² - 10x.

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3 years ago

Read 2 more answers

What 2+2 x10+2X2+10=

erastova [34]

Answer:

Step-by-step explanation:

Use PEMDAS:

2*10 is 20

2*2 is 4

So the equation is now

2+20+4+10=

Now add:

Thus the solution is 36

Hope this helps!

4 0

2 years ago

Read 2 more answers

Vadim26 [7]

Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, $\overline{AB}$ = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, $\overline{BC}$ = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, $\overline{AC}$ = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, $\overline{DE}$ = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, $\overline{EF}$ = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, $\overline{DF}$ = √((2 - 3)² + (-1 - (-3))²) = √5

∴ $\overline{AB}$ / $\overline{DE}$ = 2·√5/(√5) = 2

$\overline{BC}$ / $\overline{EF}$ = 2·√10/(√10) = 2

$\overline{AC}$ / $\overline{DF}$ = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

4 0

3 years ago

Week 1 2 3 4 5 Water Level (inches) − 1 1 4 1 3 8 2 1 2 − 1 5 8 − 1 3 4 Between which two weeks did the water level change the m

suter [353]

Answer:

The water level change the most in week 3 and week 4

The change = -370 inches

Step-by-step explanation:

Given - Week 1 2 3 4 5

Water Level (inches) − 1 1 4 1 3 8 2 1 2 -1 5 8 -1 3 4

To find - Between which two weeks did the water level change the most? Calculate the change .

Proof -

The formula for change in water level with respect to week be-

Rate of Change in Water Level = Difference in water level / Difference in weeks

Now,

For week 1 and week 2

Rate of change in water level = $\frac{138 - 114}{2 - 1}$ = $\frac{24}{1}$ = 24 inches

Now,

For week 1 and week 3

Rate of change in water level = $\frac{212 - 114}{3 - 1}$ = $\frac{98}{2}$ = 49 inches

Now,

For week 1 and week 4

Rate of change in water level = $\frac{-158 - 114}{4 - 1}$ = $-\frac{272}{3}$ = -90.67 inches

Now,

For week 1 and week 5

Rate of change in water level = $\frac{-134 - 114}{5 - 1}$ = $-\frac{248}{4}$ = -62 inches

Now,

For week 2 and week 3

Rate of change in water level = $\frac{212 - 138}{3 - 2}$ = $\frac{74}{1}$ = 74 inches

Now,

For week 2 and week 4

Rate of change in water level = $\frac{-158 - 138}{4 - 2}$ = $-\frac{296}{2}$ = -148 inches

Now,

For week 2 and week 5

Rate of change in water level = $\frac{-134 - 138}{5 - 2}$ = $-\frac{272}{3}$ = -90.67 inches

Now,

For week 3 and week 4

Rate of change in water level = $\frac{-158 - 212}{4 - 3}$ = $-\frac{370}{1}$ = -370 inches

Now,

For week 3 and week 5

Rate of change in water level = $\frac{-134 - 212}{5 - 3}$ = $-\frac{346}{2}$ = 173 inches

Now,

For week 4 and week 5

Rate of change in water level = $\frac{-134 + 158}{5 - 4}$ = $\frac{24}{1}$ = 24 inches

∴ we get

The water level change the most in week 3 and week 4

The change = -370 inches

Note :

The highest change means which temperature goes the most change in water level. It can be negative also.

So, We have to take the modulus and then find the highest number.

Here, 370 > 173

So, Highest change occurs in Week 3 and Week 4 but not in Week 3 and Week 5.

7 0

2 years ago