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Tom [10]
3 years ago
13

Write the proghrams for the following:

Computers and Technology
1 answer:
belka [17]3 years ago
5 0

Answer:

a)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c;

   cin>>a>>b;

   if(a^b)//X-OR operator in C++.

   c=true;

   else

   c=false;

   cout<<c;

return 0;

}

b)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c,d;

   cin>>a>>b>>c;

   if((a^b)^c)//X-OR operator in C++.

   d=true;

   else

   d=false;

   cout<<d;

return 0;

}

Explanation:

The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.

In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.

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Write a program that asks the user to input an integer named numDoubles. Create a dynamic array that can store numDoubles double
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Answer:

Answered in C++

#include <iostream>

using namespace std;

int main() {

   int size;

   cout<<"Length of array: ";

   cin >> size;

   double *numDoubles = new double[size];

   double sum =0;

   cout<<"Array Elements: ";

   for(int i=0;i<size;i++){

       cin>>numDoubles[i];

       sum += numDoubles[i];

   }

   delete [] numDoubles;

   cout<<"Average: "<<sum/size;

   return 0;  

}

Explanation:

This line declares the size (or length) of the array

<em>    int size; </em>

This line prompts the user for the array length

<em>    cout<<"Length of array: "; </em>

This gets the input from the user

<em>    cin >> size; </em>

This dynamically declares the array as of double datatype

<em>    double *numDoubles = new double[size]; </em>

This declares and initializes sum to 0

<em>    double sum =0; </em>

This prompts the user for elements of the array

<em>    cout<<"Array Elements: "; </em>

The following iteration gets input from the user and also calculates the sum of the array elements

<em>    for(int i=0;i<size;i++){ </em>

<em>        cin>>numDoubles[i]; </em>

<em>        sum += numDoubles[i]; </em>

<em>    } </em>

This deletes the array

<em>    delete [] myarray; </em>

This calculates and prints the average of the array

<em>    cout<<"Average: "<<sum/size; </em>

6 0
3 years ago
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