there's a chance the web server could quite possibly be backed up from all the requests and not being cleaned or updated often
Answer:
1. Mass Storage Devices
2. Available Storage Space
3. Data Access Performance
4. Device Form Factor and Connection
Answer:
<u>Call by reference</u>
In an function if the variables are passed as reference variables this means that the variables are pointing to the original arguments.So the changes made in the function on the reference variables will be reflected back on the original arguments.
For example:-
#include<stdio.h>
void swap(&int f,&int s)
{
int t=f;
f=s;
s =temp;
}
int main()
{
int n,m;
n=45;
m=85;
swap(n,m);
printf("%d %d",m,n);
return 0;
}
the values of m and n will get swapped.
<u>
Call by value</u>
In this program the values of m and n will not get swapped because they are passed by value.So duplicate copies of m and n will be created and manipulation will be done on them.
#include<stdio.h>
void swapv(int f,int s)
{
int t=f;
f=s;
s=temp;
}
int main()
{
int n,m;
n=45;
m=85;
swapv(n,m);
printf("%d %d",n,m);
return 0;
}
Answer:
//The Employee Class
public class Employee {
char name;
long ID;
//The constructor
public Employee(char name, long ID) {
this.name = name;
this.ID = ID;
}
//Method Get Person
public void getPerson (char newName, long newId){
this.ID = newName;
this.ID = newId;
}
//Method Print
public void print(){
System.out.println("The class attributes are: EmpName "+name+" EmpId "+ID);
}
}
The working of the class is shown below in another class EmployeeTest
Explanation:
public class EmployeeTest {
public static void main(String[] args) {
Employee employee1 = new Employee('a', 121);
Employee employee2 = new Employee('b', 122);
Employee employee3 = new Employee('c', 123);
employee1.print();
employee2.print();
employee3.print();
}
}
In the EmployeeTest class, Three objects of the Employee class are created.
The method print() is then called on each instance of the class.
I'm pretty sure the answer is code
