Question

What is the area of this area?????

Answer 1

Answer:

$\large\boxed{A=153\ in^2}$

Step-by-step explanation:

We have the ractangle and the trapezoid.

The formula of an area of a rectangle:

$A_{rectangle}=lw$

l - length

w - width

The formula of an area of a trapezoid:

$A_{trapezoid}=\dfrac{b_1+b_2}{2}\cdot h$

b₁, b₂ - bases

h - height

RECTANGLE:

l = 3 in, w = 16 in

$A_{rectangle}=(3)(16)=48\ in^2$

TRAPEZOID:

b₁ = 16 in, b₂ = 5 in, h = 10 in

$A_{trapezoid}=\dfrac{16+5}{2}\cdot10=\dfrac{21}{1}\cdot5=105\ in^2$

The area of the figure:

$A=A_{rectangle}+A_{trapezoid}$

Substitute:

$A=48+105=153\ in^2$

Answer 2

Answer:

  =153 in^2

Step-by-step explanation:

We have  a rectangle and a trapezoid

We can add the areas together

The area of the rectangle is

A = l*w  where l =16 and w =3

A = 16*3 = 48 in^2

The area of the trapezoid

A = 1/2 (b1+b2)*h  where b1 =16, b2=5 and h = 10

A = 1/2 (16+5) *10

   = 1/2 (21) *10

   =105 in^2

Then we add the areas together

A total = A rectangle + A trapezoid

A total = 48+ 105

           =153 in^2