9514 1404 393
Answer:
3. 7
Step-by-step explanation:
The distance formula applies in 3 dimensions as well as 2.
d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)
d = √((-2)² +6² +3²) = √(4 +36 +9) = √49
d = 7
The distance between the two points is 7 units.
Answer:
I believe it's the one on the bottom left
Step-by-step explanation:
I'm still taking my test so I'll come back later to tell you if it's correct.
First 0-0=0
Next 5-5=0
Then 4-3=1
After 3-1=2
Then 1-1=0
Move comma after 2
(xy)' + (2x)' + (3x^2)' = (4)'
y + xy' + 2 + 6x = 0
xy' = -y -2 -6x
y' = [-y -2 -6x] / x
Now solve y from the original equation and substitue
xy + 2x + 3x^2 = 4 => y = [-2x - 3x^2 + 4] / x
y' = [(-2x - 3x^2 +4) / x - 2 - 6x ] / x
y' = [-2x - 3x^2 + 4 -2x -6x^2 ] x^2 = [ -4x - 9x^2 + 4] / x^2 =
= [-9x^2 - 4x + 4] / x^2
Answer:
Step-by-step explanation:
lm=6x+3
mn=4x-17
ln=x+14
lm+mn>ln
6x+3+4x-17>x+14
10x-14>x+14
9x>28
x>28/9
mn+ln>lm
4x-17+x+14>6x+3
5x-3>6x+3
-x>6
x<-6
lm+ln>mn
6x+3+x+14>4x-17
7x+17>4x-17
3x>-34
x>-34/3
combining x<-6 or x>28/9
