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irina [24]
3 years ago
10

Which function is represented by the graph below?

Mathematics
2 answers:
zhuklara [117]3 years ago
8 0

Answer:

f(x) = 3x + 3

Step-by-step explanation:


Bad White [126]3 years ago
6 0
Good day ~_~ /////////////

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How do I rename the number 5 hundreds 8 tens
Phantasy [73]
5 hundred is 500

8 tens is 80

So 5 hundred 8 tens is <em><u>580</u></em>

7 0
3 years ago
Read 2 more answers
Last question and then I’ll take care of the rest on my own ^^^^
Bond [772]

Answer:

  (c)  5/2

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

  a^-b = 1/a^b

__

Using these rules, we can simplify the expression as follows:

  (5^-3)(2^2)(5^6)/((2^3)(5^2)) = (5^(-3+6-2))(2^(2-3)) = (5^1)(2^-1)

  = 5/2

6 0
2 years ago
Which value of I makes the equation 6 (0.52 – 1.5) + 20 =-9- (1 + 6) true? 0 - 14 O1 14​
Virty [35]
-1 you are correct about that answer
6 0
3 years ago
Exercise 3.5. For each of the following functions determine the inverse image of T = {x ∈ R : 0 ≤ [x^2 − 25}.
masya89 [10]

a. The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

b. The inverse image of g(x) is g^{-1}(x) = e^{x}

c. The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

<h3 /><h3>The domain of T</h3>

Since T = {x ∈ R : 0 ≤ [x^2 − 25} ⇒ x² - 25 ≥ 0

⇒ x² ≥ 25

⇒ x ≥ ±5

⇒ -5 ≤ x ≤ 5.

<h3>Inverse image of f(x)</h3>

The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

f : R → R defined by f(x) = 3x³

Let f(x) = y.

So, y = 3x³

Dividing through by 3, we have

y/3 = x³

Taking cube root of both sides, we have

x = ∛(y/3)

Replacing y with x we have

y = ∛(x/3)

Replacing y with f⁻¹(x), we have

So,  the inverse image of f(x) is f⁻¹(x) = ∛(x/3)

<h3>Inverse image of g(x)</h3>

The inverse image of g(x) is g^{-1}(x) = e^{x}

g : R+ → R defined by g(x) = ln(x).

Let g(x) = y

y =  ln(x)

Taking exponents of both sides, we have

e^{y} = e^{lnx} \\e^{y} = x

Replacing x with y, we have

y = e^{x}

Replacing y with g⁻¹(x), we have

So, the inverse image of g(x) is g^{-1}(x) = e^{x}

<h3>Inverse image of h(x)</h3>

The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

h : R → R defined by h(x) = x − 9

Let y = h(x)

y = x - 9

Adding 9 to both sides, we have

y + 9 = x

Replacing x with y, we have

x + 9 = y

Replacing y with h⁻¹(x), we have

So, the inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

Learn more about inverse image of a function here:

brainly.com/question/9028678

5 0
2 years ago
(7 * 10-5) (5 x 10-) =<br><br>x 10​
blagie [28]

Have you learned PEMDAS? (Parenthesis, exponents, multiplication, division, addition, subtraction). That is what I am going to do here.

The first parenthesis, let's solve. 7*10=70-5=65

The second parentheisis: I am assuming the negative sign is a typo, and this answer will be off if it is not. Sorry. 5*10=50

65*50=3250

I hope this helps, and let me know if you need further assistance.

8 0
3 years ago
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