Answer:
-15
Step-by-step explanation:
Remember to follow PEMDAS. PEMDAS =
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
Solve the parenthesis:
(2 + 8 - 8) = (10 - 8) = 2
Divide: -30/2 = -15
-15 is your answer.
H= -8. H-2h= 9-1; -h=8; h= -8
Answer:
The equation of the blue graph is g(x)=(x-3)^{2} +1g(x)=(x−3)
2
+1 . Below is the explanation
Step-by-step explanation:
Given:
The graph of f(x)=x^{2}x
2
To find:
The equation of the transformed graph g(x).
The red graph f(x) is moved right 3 units and up 1 unit to get g(x).
When graph is moved right 3 units , 3 should be subtracted with x.
When graph is moved up 1 unit, 1 is added at the end.
So, our g(x)=(x-3)^{2} +1(x−3)
2
+1
The equation of the blue graph is g(x)=(x-3)^{2} +1g(x)=(x−3)
2
+1
The answer is= n= 11/2 and in decimal it’s n=5.5
Explanation:
You first move the constant to the right
4n=16+6 you then calculate which will be 4n=22 and then you divide both sides
Add 1 to both sides:

In cases like this, we have to remember that a root is always positive, so we can square both sides only assuming that

Under this assumption, we square both sides and we have

The solutions to this equation are

But since we can only accept solutions greater than -1, we discard
and accept
.
In fact, we have

and

which is the only solution.