Answer:
![\boxed{\boxed{\text{Run}=120}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Ctext%7BRun%7D%3D120%7D%7D)
Step-by-step explanation:
From coordinate geometry we know that, slope is ratio of vertical change rise and the horizontal change run.
Mathematically,
![\text{Slope}=\dfrac{\text{Rise}}{\text{Run}}](https://tex.z-dn.net/?f=%5Ctext%7BSlope%7D%3D%5Cdfrac%7B%5Ctext%7BRise%7D%7D%7B%5Ctext%7BRun%7D%7D)
Putting the given values,
![\Rightarrow \dfrac{1}{20}=\dfrac{6}{\text{Run}}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B1%7D%7B20%7D%3D%5Cdfrac%7B6%7D%7B%5Ctext%7BRun%7D%7D)
![\Rightarrow \text{Run}=6\times 20](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ctext%7BRun%7D%3D6%5Ctimes%2020)
![\Rightarrow \text{Run}=120](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ctext%7BRun%7D%3D120)
Answer:
140°
Step-by-step explanation:
The value of supplement is 40 and X. We know that the sum of the sumplementary angles is 180. Therefore ,
=> x + 40° = 180°
=> x = 180° - 40°
=> x = 140°
<h3>
<u>Hence </u><u>the</u><u> </u><u>value </u><u>of </u><u>x </u><u>is </u><u>1</u><u>4</u><u>0</u><u>°</u><u> </u><u>.</u></h3>
Answer:
v=2 s=5
Step-by-step explanation:
a) v=volleyball s=soccer
s × v = 7
" the soccer (s) practice lasts 1 hour (1) more than (+) twice as long (2) as the volleyball (v) practice; this simplifies to: s = 1 + 2v
b) substitute equation for soccer for s
(1 + 2v) + v = 7
solve for v
1 + 3v = 7 (2v + v = 3v; that's where the 3v comes from)
we subtract 1 from both sides
3v = 6
we divide 3 from both sides
v=2
solve for s
since we know what v equals, we substitute it in
s + 2 =7
subtract 2 from both sides
s = 5
Answer:
3139.5 m²
Step-by-step explanation:
the formula for the volume of a sphere of radius r is V = (4/3)πr³. In this particular case, V = 2098π m³ = (4/3)πr³, and from this we can calculate the radius, r:
2098π m³
r³ = ----------------- = (3/4)(2098 = 1483/5
(4/3)π
Thus r = ∛1573.5 m³ = 11.64 m
Then the surface area is A = 4πr², which in this case is
A = 4(3.14159)(11.64 m)^2 = 1702.6 m² (which is to the nearest tenth).