The length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Since Kristin wants to wrap a ribbon around the perimeter of a rectangle, the perimeter of a rectangle P = 2(L + W) where L = length of rectangle and W = width of rectangle.
Given that the perimeter of the rectangle, P = 56 inches and the length of the rectangle, L is five less than twice the width of the rectangle, W we have that
L = 2W - 5
Substituting L into P, we have
P = 2(2W - 5 + W)
P = 2(W - 5)
Since P = 56, we have
2(W - 5) = 56
~Dividing both sides by 2, we have
W - 5 = 56/2
W - 5 = 23
Adding 5 to both sides, we have
W = 23 + 5
W = 28 inches
Substituting W into L, we have
L = 2W - 5
L = 2(28) - 5
L = 56 - 5
L = 51 inches
So, the length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
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6.95
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The third choice
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We need to find the slope and y-intercept of the line and then put it into y = mx = b form. To find the slope, pick a point on the line; I will use (-2, 5); count how many units up you need to go to get to the next point on the line, which in this case it would be 3. The count how many to the right or left you would need to go, which is 1 to the left. Moving left means a negative, so it is -1. Your slope fraction would be
, since slope is rise over run. You can sub this fraction in for m in y = mx + b, which will give you a revised equation of y = -3x = b. To find the y intercept, or b, just find the point where the line crosses the y-axis, which is -1. So, the equation is now y = -3x - 1.The correct answer is third choice.
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x=-1
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5x2−9x=7 (Option B)
Step-by-step explanation:
this is correct 100%