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2 years ago

Determine the perimeter of the shape. Determine the area of the shape in two ways.

Mathematics

1 answer:

gogolik [260]2 years ago

6 0

Perimeter: Add up all of the sides of a shape

Area: Length times width

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Help on this please I’d appreciate it

maxonik [38]

<h2>Finding the y-intercept given the Graph of the Line</h2>

Answer:

The $y$ -intercept is $\boxed{3}$

Step-by-step explanation:

The $y$ -intercept of line is just the point where the $y$ -axis and the line. From the given line, we can see that the $y$ -axis and the line that models the temperature on a certain winter day since sunrise $(0,3)$ . Also, the question just asked us for the $y$ -coordinate of the $y$ -intercept so $3$

6 0

3 years ago

Can you extend the zero product property to non zero products of numbers? For example, if ab=8, is it always true that a=8 or b=

larisa [96]

That is not always true because think of it as ab=8 that is just like saying (8)(8)=8 which is absolutely false. If anything it can be either a or be equals 8 while the other variable is 1. (1)(8)=8 or (8)(1)=8

4 0

3 years ago

P = 0.5e - 5 to determine P

ipn [44]

Answer:

Let's solve your equation step-by-step.

p=(0.5)(2.718282)−5

Step 1: Simplify both sides of the equation.

p=(0.5)(2.718282)−5

p=1.359141+−5

p=(1.359141+−5)(Combine Like Terms)

p=−3.640859

Answer:

p=−3.640859

Step-by-step explanation:

6 0

3 years ago

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

4 years ago

7th grade slope help me

svlad2 [7]

Answer:

A, C

Step-by-step explanation:

When you put the equation y = x -12 into a TI-84 calculator (because it has graph) and go to the table you can see that B,D,E don’t have the same y-axis even though their x-axis is the same but the y-axis isn’t, therefor A and C is the correct answer.

Sorry not the best explanation but I hope it helps

6 0

3 years ago