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FinnZ [79.3K]
4 years ago
8

Solve: -7 < 2x+5 < 7

Mathematics
1 answer:
kondor19780726 [428]4 years ago
4 0

Answer:

- 6 < x < 1

Step-by-step explanation:

first things first:

- 7 < 2x  + 5 \\  - 7 - 5 < 2x  + 5 - 5 \\  - 12 < 2x \\  - 6 < x

now:

2x + 5 < 7 \\ 2x + 5 - 5 < 7 - 5 \\ 2x < 2 \\ x < 1

now the intersection is:

- 6 < x < 1

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PLZ I REALLY NEED HELP!
allochka39001 [22]
1.) That just means that X will equal 8, so the same as:
3(8)-1
24-1
23

2.)
The relationship is a function, there are no repeated elements in the domain(x column), and each domain is pair with one element in the range.
The function is y = 2x+1, when you double x and add 1, you get y.

3.) The relation is not a function for reasons I explained in 2.), x is paired with more than 1 element. The domain is 1,3,-5. Range is -2,2,0,4,-4
6 0
4 years ago
Help Assap with this question.
exis [7]
(-2,2)(2,-2)
slope = (-2 - 2) / (2 - (-2) = -4/4 = -1

as far as point slope form, there can be 2 answers...

y - y1 = m(x - x1)
slope(m) = -1
using points (-2,2)...x1 = -2 and y1 = 2
now we sub
y - 2 = -1(x - (-2) =
y - 2 = -1(x + 2) <== or could be written as y - 2 = - (x + 2)

y - y1 = m(x - x1)
slope(m) = -1
using points (2,-2)...x1 = 2 and y1 = -2
now we sub
y - (-2) = -1(x - 2) =
y + 2 = -1(x - 2) <== or can be written as y + 2 = - (x - 2)

either one of those answers is ur point slope form
5 0
3 years ago
Simplify 6x+9/15x2 over 16x-12/10x4
Alexeev081 [22]

Answer: 3 • (x + 10)

———————————————

- 41

5 0
3 years ago
Find the root of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2x%20%7B%20%7D%5E%7B2%7D%20%7D%20%20%2B%20x%20%2B%20%20%5Csq
artcher [175]

Answer:

The root of    x = -2 + √2

Step-by-step explanation:

<u><em> Step(i):-</em></u>

Given \sqrt{2x^{2} } + x +\sqrt{2} = 0

      ⇒    \sqrt{2} } ( x^2 ) ^{\frac{1}{2} } + x +\sqrt{2} = 0

      ⇒   \sqrt{2}x  + x +\sqrt{2} = 0

     ⇒      (\sqrt{2}  + 1) x = - \sqrt{2}

           x = \frac{-\sqrt{2} }{(\sqrt{2}  + 1)}

<u><em>Step(ii):-</em></u>

Rationalizing

     x = \frac{-\sqrt{2} }{(\sqrt{2}  + 1)} X \frac{(\sqrt{2}  - 1)}{(\sqrt{2}  - 1)}

Apply ( a-b ) ( a+b) = a²-b²

    x = \frac{-\sqrt{2}(\sqrt{2} -1) }{(\sqrt{2})^{2}   - 1^{2} )} = \frac{-(2-\sqrt{2} }{2-1}

The root of    x = -2 + √2

6 0
3 years ago
Solve the following expression when<br> v = 10 and e= 5<br> 2v ÷ e + 3​
Montano1993 [528]

Hello!

Answer:

5/2 or 2.5

Step-by-step explanation:

<em>Plug in the numbers for v and e </em>

2(10)÷5+3

20÷8

5/2 or 2.5

Hope this helps!

6 0
3 years ago
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