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3 years ago

Put the integers in least to greatest -6, 3, -12, -8, 15, -13, 4, 10, -14, 2, 11

Mathematics

2 answers:

Strike441 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

-14,-13,-12,-8,-6,2,3,4,10,11,15

seropon [69]3 years ago

3 0

Answer:

-14, -13, -12, -8, 2, 4, 10, 11, 15

Step-by-step explanation:

Think of it as a number line.

0 is in the middle and count up on both sides. Only the left of the 0 the numbers are negative

ex:

<------------------------>

-3 -2 -1 0 1 2 3

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tamaranim1 [39]

Answer:

3000

Step-by-step explanation:

640x3 = 1920

90x12 = 1080

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1 year ago

can put $11 of his allowance and in his savings account every week call how much money will he have after 15 weeks

dlinn [17]

11 x 15 = 165. he would have 165$

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3 years ago

Read 2 more answers

A system of two linear equations with two variables is shown below.

Orlov [11]

{ 3-y=2x
{ x+1/2y=3/2

{ -y=2x-3
{ 1/2y=3/2-x

{ y=-2x+3
{ y=3-2x

-2x+3=3-2x

(x,y) = (x,-2x+3)

6 0

2 years ago

How would I do this question.

olga2289 [7]

Answer:

The density of cube is 6.17959 $\frac{g}{cm^{3} }$

Step-by-step explanation:

The density is given by ration of a mass of body and volume occupied by a body.

$\rho = \frac{m}{V}$

Where,

$\rho$ is density.

m is mass of a body

V is the volume of a body

Given that one side of the cube is 0.53cm

Hence, the volume of a body is V= $0.53^{3}$ =0.148877 $cm^{3}$

Now, the Density of the cube will be

$\rho = \frac{m}{V}$

$\rho = \frac{0.92}{0.148877}$

$\rho =6.17959$

Thus, The density of cube is 6.17959 $\frac{g}{cm^{3} }$

3 0

3 years ago

A box of donuts containing 6 maple bars, 3 chocolate donuts, and 3 custard filled donuts is sitting on a counter in a work offic

Svetlanka [38]

Probabilities are used to determine the chances of selecting a kind of donut from the box.

The probability that Warren eats a chocolate donut, and then a custard filled donut is 0.068

The given parameters are:

$\mathbf{Bars = 6}$

$\mathbf{Chocolate = 3}$

$\mathbf{Custard= 3}$

The total number of donuts in the box is:

$\mathbf{Total= 6 + 3 + 3}$

$\mathbf{Total= 12}$

The probability of eating a chocolate donut, and then a custard filled donut is calculated using:

$\mathbf{Pr = \frac{Chocolate}{Total}\times \frac{Custard}{Total-1}}$

So, we have:

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{12-1}}$

Simplify

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{11}}$

Multiply

$\mathbf{Pr = \frac{9}{132}}$

Divide

$\mathbf{Pr = 0.068}$

Hence, the probability that Warren eats a chocolate donut, and then a custard filled donut is approximately 0.068