<h3>
Answer:</h3>
5 units
<h3>
Step-by-step explanation:</h3>
A point 4 up and 3 over from its original location has moved a distance that can be found using the Pythagorean theorem.
... d² = 4² +3² = 16 +9 = 25
... d = √25 = 5 . . . . units
Answer:
a=9+6
p=-30+20
z=15+(-12)
x=-10+(-7)
Step-by-step explanation:
Answer:
30
Step-by-step explanation:
200*0.15=30
Answer:
Tn=a + (n-1)d
a= first term = 14
n= This is the term you're looking for... In this case... That's the 73rd term
d=Common difference (since its an AP)
d= second term - first term -- Or 3rd term - 2nd term = 23-14
d=9
T = 14 + (73-1)9
T= 14 + (72)9
T= 14 + 648
T=662.
Answer:
Initial height or what the ball was originally bounced from a height of 9 feet
Step-by-step explanation:
9 represents the height that the ball was originally bounced from.
If you plug in 0 for 
into 
, you get:
.
9 feet is the initial height since that is what happens at time zero.
