Answer:
The answer is "266.5".
Step-by-step explanation:
Given value:

find:
Sample mean=?


Answer: Tigers = 46 Bears = 44
<u>Step-by-step explanation:</u>
Let x represent the numbers of points scored by the Bears.
then x + 2 is the number of points scored by the Tigers.
Bears + Tigers = Total
x + x + 2 = 90
2x + 2 = 90
2x = 88
x = 44
Bears (x) = 44
Tigers (x + 2) = 44 + 2 = 46
I think is a because if you see and do it you could see
1/5, .35, 12/25, .50, 4/5
Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)