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marta [7]
3 years ago
12

Which of the terms heat of vaporization and heat of fusion refers to condensation and which refers to melting?

Chemistry
1 answer:
navik [9.2K]3 years ago
3 0

Answer:

Heat of vaporization refers to condensation and heat of fusion refers to melting.

Explanation:

Heat of vaporization or heat of evaporation, is defined as the energy required to convert liquid substance into a gas which creates condensation. As a gas condenses to a liquid, heat is released.

Heat of fusion refers to melting because heat of fusion is defined as the energy required to change any amount of substance when it melts.

Hence, the correct answer is "Heat of vaporization refers to condensation and heat of fusion refers to melting.".

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Which of the following compounds is not likely to have ionic bonds LiF, NaCI, CH4, MgF2
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Methane CH_{4} does not have ionic bonds. Because of the close value of electronegativity of the carbon and hydrogen atoms the electrons are shared forming covalent bonds.

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1. What type of acid is used in automobile batteries? How does this acid cause a battery to work?
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battery acid is the type of acid used in your cars battery

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4 years ago
A multi-nutrient fertilizer contains several different nitrogen containing compounds. The fertilizer is 54.8% CH4N2O (urea), 26.
vesna_86 [32]

Answer:

  • <u><em>9.01 g of fertilizer</em></u>

Explanation:

Assume initially that the amount in grams of the multinutrient fertilizer is 100 g, and calculate the amount of nitrogen supplied by every compound present in these 100 g of fertilizer.

<u>1) Urea (CH₄N₂O)</u>:

  • Molar mass of urea: 60.06 g/mol
  • Atomic mass of N: 14.007 g/mol
  • Total mass of N in the formula: 2 × 14.007 g/mol = 28.014 g/mol
  • Amount of N in 100 g of compound: 100 g × 54.8% × 28.014 g / 60.06 g =  25.56 g

<u>2) KNO₃</u>

  • Molar mass of KNO₃: 101.1032 g/mol
  • Atomic mass of N: 14.007 g/ mol
  • Total mass of N in the formula: 14.007 g/mol
  • Amount of N in 100 of the compound: 100 g × 26.3% × 14.007 / 101.1032 = 3.64 g

<u>3) (NH₄)₂PO₄</u>

  • Molar mass of (NH₄)₂PO₄: 132.06 g/mol
  • Atomic mass of N: 14.007 g/ mol
  • Total mass of N in the formula: 2×14.007 g/mol = 28.014 g/mol
  • Amount of N in 100 of the compound: 100 g × 14.1% × 14.007 / 132.06 = 2.99 g

4) <u>Total mass of N in 100 g of fertilizer</u>:

Add all the amounts of N obtained above

  • 25.56g + 3.69 g + 2.99 g = 32.19 g of N

5) <u>Mass of fertilizer that should be applied to provide 2.90 g of N to a plant</u>.

Set a proportion:

  • 32.19 g of N / 100 g of fertilizer = 2.90 g of N / X

Solve for X:

  • X = 2.90 g of N × 100 g of fertilizer / 32.19 g of N = 9.01 g of fertilizer

That is the answer: 9.01 g of fertilizer should be applied to provide 2.90g  of N to a plant.

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Answer:

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Explanation:

The general trend is for ionisation energies to increase across a period. In the whole of period 2, the outer electrons are in 2-level orbitals - 2s or 2p. ... That causes greater attraction between the nucleus and the electrons and so increases the ionisation energies.

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Answer:

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