Recall that the LL theorem, as well as the LA theorem, both apply only to right-triangles.
now, in the LL, if a right-triangle has congruent Legs with another, both right-triangles are congruent.
in the LA, if a right-triangle has one Leg and one Angle congruent with another right-triangle, then they're congruent.
well, in the LA, once you have a Leg and then an Angle touching that Leg, the angle is also touching another Leg, since it is an angle and is cornered by two Legs. The second Leg touched or stemming from that Angle, can only be of one possible length, because the first Leg and the Angle will constrain it to be of certain length.
and that is true for both triangles, and since both triangles will have a second Leg constrained to be a certain length, because of LA, then a second Leg will also be congruent on both right-triangles, so the theorem kinda becomes LAL theorem, Leg Angle Leg, but we can just do away with the Angle part and call it LL.
130, - 12, 56.1, 11.2
these are all arithmetic sequences with n th term formula
= 
+ (n - 1 )d
where d is the common difference and the first term
(1)
d = 10 - 4 = 4 - (- 2 ) = 6 and = - 14
= - 14 + (24 × 6) = - 14 + 144 = 130
(2)
d = 14 - 16 = 16 - 18 = - 2 and = 22
= 22 + (17 × - 2 ) = 22 - 34 = - 12
(3)
= 2.2 + (49 × 1.1) = 2.2 + 53.9 = 56.1
(4)
= - 4.2 + (11 × 1.4 ) = - 4.2 + 15.4 = 11.2
I would need more information since you must use trig to find the value
I would need to know where they are located in order to find cos of H correctly
Y= <span><span><span>−25
--------- x
8
H
O
P
E
THIS HELPS!</span></span></span>
