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3 years ago

Suppose that a sequence is defined as follows. This the 1st four terms of the sequence. ASAP BRANLIEST TY!!

Mathematics

1 answer:

SashulF [63]3 years ago

5 0

Answer:

- 3, 16, - 22, 54

Step-by-step explanation:

Using the recursive formula with a₁ = - 3, then

a₂ = - 2a₁ + 10 = - 2(- 3) + 10 = 6 + 10 = 16

a₃ = - 2a₂ + 10 = - 2(16) + 10 = - 32 + 10 = - 22

a₄ = - 2a₃ + 10 = - 2(- 22) + 10 = 44 + 10 = 54

Thus

the first 4 terms of the sequence are

- 3, 16, - 22, 54

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3 years ago

Drag and drop each number to its correct position on the number line.

Stels [109]

Answer:

-⅜ is between -1 and 0

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3 years ago

An isosceles triangle’s altitude will bisect its base. Which expression could be used to find the area of the isosceles triangle

omeli [17]

Answer:

$\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}$

Step-by-step explanation:

The length of the base is the distance between the points 4+2i and 10+4i, so

$\text{Base}=|10+4i-(4+2i)|=|10+4i-4-2i|=|6+2i|=\sqrt{6^2+2^2}=\\ \\=\sqrt{36+4}=\sqrt{40}$

The middle point of the base is placed at point

$\dfrac{4+2i+10+4i}{2}=\dfrac{6i+14}{2}=7+3i$

The length of the height is the distance between the points 5+9i and 7+3i

$\text{Height}=|5+9i-(7+3i)|=|5+9i-7-3i|=|-2+6i|=\sqrt{(-2)^2+6^2}=\\ \\=\sqrt{4+36}=\sqrt{40}$

So, the area of the triangle is

$A=\dfrac{1}{2}\cdot \text{Base}\cdot \text{Height}=\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}$

4 0

3 years ago

The angles of elevation froma point X to the top of flagpoles A and B are 35* and 45* respectively. If X lies in the middle of t

BartSMP [9]

Let AB = t. And since X lies in the middle, so AX=BX = t/2 .

Let the height of the smaller flagpole is AO and of larger flagpole is BP .

Using tangent ratio rule in each triangle, we will get

$tan 35 =\frac{AO}{t/2} , tan 45= \frac{BP}{t/2} // AO = \frac{t*tan35}{2}, BP=\frac{t*tan45}{2}$

And there ratio is

$\frac{AO}{BP}= \frac{tan 35}{tan 45}=\frac{0.7}{1}$

5 0

3 years ago

Find the angle between the given vectors to the nearest tenth of a degree. u = (8, 4), v = (9, -9)

Usimov [2.4K]

Answer:

71.6 degrees

Step-by-step explanation:

The formula for calculating the angle between two vectors is expressed as;

u.v = |u||v|cos theta

u.v = (8, 4).(9, -9)

u.v = 8(9)+4(-9)

u.v = 72-36

u.v = 36

|u| = √8²+4²

|u| = √64+16

|u| = √80

|v| = √9²+(-9)²

|v| = √81+81

|v| = √162

36 = √80*√162 cos theta

36 = √12960 cos theta

36 = 113.84 cos theta

cos theta = 36/113.84

cos theta = 0.3162

theta = arccos (0.3162)

theta = 71.6 degrees

Hence the angle between the given vectors is 71.6 degrees

7 0

3 years ago

Read 2 more answers

Suppose that a sequence is defined as follows. This the 1st four terms of the sequence. ASAP BRANLIEST TY!!​

Suppose that a sequence is defined as follows. This the 1st four terms of the sequence. ASAP BRANLIEST TY!!